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Brut [27]
3 years ago
14

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
dexar [7]3 years ago
7 0

Answer:

We start on the number -3 on the number line. Since the b > -3 is using the greater than sign, it is an open circle and since the inequality is pointing to the right, we can draw the arrow going to the right on the number line.

Step-by-step explanation:

\dfrac{ b  }{ 3  }  +1 > 0

Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.

b+3 > 0

Subtract 3 from both sides. Anything subtracted from zero turns into a negative number.

b+3-3 > 0-3

Simplify

b > -3

Now we need to graph it:

Inequalities can be shown on a number line. Open circles are used for numbers that are less than or greater than (< or >). Closed circles are used for numbers that are less than or equal to and greater than or equal to (≤ or ≥).

Symbol Meaning

> Greater than

> Greater than or equal to

< Less than

< Less than or equal to

We start on the number -3 on the number line. Since the b > -3 is using the greater than sign, it is an open circle and since the inequality is pointing to the right, we can draw the arrow going to the right on the number line.

Also look at the picture

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A number is chosen at random from 1 to 10. Find the probability of not selecting
PilotLPTM [1.2K]

Answer:

0.3

Step-by-step explanation:

Number of ways of selecting  r elements from a set of n different elements is given by

C(n,r)=(n r)=n!/(r!(n−r)!)

No of ways of selecting one number out of ten numbers from one to 10 is 10

It can also be calculated using  

C(n,r)=(n r)=n!/(r!(n−r)!)

where n = 10 and r = 1

C(10,1)=(10 1)=10!(1!(10−1)!) = 10*9!/ 1!*9! = 10

multiples of 2 in range 1 to 10 are 2, 4, 6, 8 , 10

multiples of 3 in range 1 to 10 are 3, 6, 9

Therefore number which are multiple of 2 and 3 are

2, 3,4,6,8,9,10   ( 7 numbers)

therefore no of ways of selecting multiple of 2 and 3 is 7 ways

number which are not multiple of 2 and 3 in range 1 to 10

1,5,7  (3 numbers)

no of ways of not selecting multiple of 2 and 3 is 3 ways

It can also be calculated using  

C(3,1)=(3 1)=3!/(1!(3−1)!)

where n = 3 and r = 1

C(3,1)=(3 1)=3!/(1!(3−1)!) =  3!/(1!(2)!)= 3*2!/ 1!*2! = 2

Therefore no of ways of not selecting multiple of 2 and 3 is 3 ways

probability of  not selecting  a multiple of 2 or a multiple of 3 =  no of ways of not selecting multiple of 2 and 3 /No of ways of selecting one number out of one to 10  = 3/10 = 0.3

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Answer:

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Step-by-step explanation:

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