we are given

now, we can compare it with

we can find b
we get

now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8

b=1.6

b=1.4

b=1.2

now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
Jack has 2, Maria has 9, Paul has 5.
In mathematics, the Laplace transform is an integral transform named after its inventor Pierre-Simon Laplace. It transforms a function of a real variable t to a function of a complex variable s.
2x+10y I thinks that’s the answer mb
The criteria to find out the x-intercept of the line is we find out the result when
y = 0
- 2x + 5y = -20
- 2x + 0 = -20
x = -20 / -2
x = 10
hope this helps