First you would simplify the equation <span>(7x²+2x+5)+(3x²-8x-10) lets start with the first part
</span><span>(7x²+2x+5)
</span>7x² + 2x which = 49x + 2x which also = 51x Then you add the last part (+5)
51x + 5
Now you simplify the last part.
<span>(3x²-8x-10)
</span>3x²-8x which=9x - 8x which also = 1x or simply x Then add the last part (-10) Which you'll get x-10
51x + 5) + (x - 10) = 52x -5
so your answer is 52x - 5
P = L + L + w + w
72 = 2(L) + 2(L-4)
Distribute
72 = 2(L) + 2(L) - 8
Add like terms
72 = 4(L) - 8
Subtract 8 from both sides
64 = 4(L)
Divide both sides by 4
16 = L
The length is 16. Now substitute that in the equation for finding w.
w = L - 4
w =
Answer:
$y=(7/2)x+20$
Step-by-step explanation:
SInce the gradient of the first line is $-2/7$ then the gradien of the perpendicular line is $7/2$.
Therefore by the point slope formula the line that we are looking for is
$y-6=(7/2)(x+4)$
$y=(7/2)x + 20$
From the Special Triangle Theorem, the hypotenuse is equal to the side lengtht times the Sqrt(2).
So hypotenuse H = xSqrt(2), x=H/Sqrt(2).
Using numbers, if H = 7, then x = 7/Sqrt(2) = 7Sqrt(2)/2 to rationalize it.
