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Vanyuwa [196]
3 years ago
5

What is the midpoint between the points (1, 4) and (-3, 2)?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
6 0
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
%  (c,d)
&({{ -3}}\quad ,&{{ 2}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -3}} + {{ 1}}}{2}\quad ,\quad \cfrac{{{ 2}} + {{ 4}}}{2} \right)
katovenus [111]3 years ago
4 0
Your midpoint is (-1, 3)
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Simplify 24x5 y6 . A) 2x2 y3 6x B) 4x2 y3 6x C) 6x2 y3 4x D) 6x2 y3 2x
Cerrena [4.2K]

Answer : A 2x^2y^3\sqrt{6x}

\sqrt{ 24x^5y^6}

Take square root for each term and simplify it

\sqrt{24} *\sqrt{x^5}  *\sqrt{y^6}

\sqrt{24}=\sqrt{4 * 6}  = 2\sqrt{6}

\sqrt{x^5} = x^2\sqrt{x}

\sqrt{y^6} = y^3

so we will get

2\sqrt{6} *  x^2\sqrt{x} * y^3

2x^2y^3\sqrt{6x}

4 0
3 years ago
Chara sold 52 boxes of candy for her marching band fundraiser. The large box costs $3.50 each and the small box costs $1.75 each
Ahat [919]

Answer:

The number of boxes of candy sold are:

40 small boxes and

12 large boxes of candy.

Step-by-step explanation:

Let the number of small boxes sold = x

Let the number of large boxes sold = y

we are given the following information:

x + y = 52 - - - - - -(1)   (Chara sold 52 boxes of candy)

3.5(y) + 1.75(x) = 112 - - - - - - (2)   (Chara sold $112 worth of candy)

From the two equations above, x and y can be solved as follows:

x + y = 52   - - - - - -(1)

x = 52 - y    - - - - - - (3)

putting the value if x in equation (3) to replace x in equation (2);

3.5(y) + 1.75(x) = 112 - - - - - - (2)

3.5(y) + 1.75(52 - y) = 112

3.5y + 91 - 1.75y = 112

(3.5y - 1.75y) + 91 = 112

1.75y = 112 - 91 = 21

y = 21 ÷ 1.75 = 12

y = 12

Now, let us put the value of y into equation (3)

x = 52 - y    - - - - - - (3)

x = 52 - 12 = 40

Therefore,

40 small boxes and 12 large boxes of candy were sold.

7 0
3 years ago
Pls help I’ll brainlest
Kipish [7]

yo bro nice pic really good quality

8 0
2 years ago
Mediam of 50+45+49+50+43+49+45+49+45+47+44+51+51+44+47+46+50+44+51+49+43+43+49+45+46+45+51+46
Doss [256]

Answer:

The median is equal 46.5

Step-by-step explanation:

to find the median, we will need to rearrange the numbers in ascending order, so we will have

43, 43, 43, 44, 44, 44, 45, 45, 45, 45, 45, 46, 46, 46, 47, 47, 49, 49, 49, 49, 49, 50, 50, 50, 51, 51, 51, 51

Note that there are 28 numbers in total, therefore the median will fall in between the fourteenth and the fifteenth number which are 46 and 47 respectively.

Since we are considering two figures as median, we will need to find the average, which will be

(46 + 47)/2 = 46.5

The median is therefore 46.5

8 0
3 years ago
The federal government spends $25.2 million each year to operate parks and historic sites in Washington D.C. This is $7.8 millio
Ray Of Light [21]

Answer:

y + 7.8 = 25.2

y = 17.4

Step-by-step explanation:

y + 7.8 = 25.2

(now we solve the equation .... we substract 7.8 from each side of the equation )

y = 25.2 - 7.8

y = 17.4

5 0
3 years ago
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