Answer:
Step-by-step explanation:
Here is a picture of the answer, since I couldn't put into words!
Answer: Un alambre de acero de 1.5 m se estira 2.0 mm con fuerza F. El diámetro del alambre de acero es 4.0 mm. El módulo de Young del acero es 2.0 x 1011 Nm-2. Determine la fuerza F aplicada sobre el alambre.
Step-by-step explanation:
Answers:
The next two terms are 67.5 and 101.25 in that order.
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Explanation:
Divide the second term over the first to get 30/20 = 1.5
Divide the third term over the second term to get 45/30 = 1.5
The common ratio is 1.5, which means we multiply 1.5 by each term to get the next term
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fourth term = 1.5*(third term) = 1.5*45 = 67.5
fifth term = 1.5*(fourth term) = 1.5*67.5 = 101.25
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As a shortcut you can plug n = 4 and n = 5 into the function t(n) = 20*(1.5)^(n-1) to get the fourth and fifth terms respectively.
