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Llana [10]
3 years ago
15

The Open Systems Interconnection (OSI) is a conceptual model whose purpose is to make networks more manageable. Its objectives i

nclude allowing for more portable hardware and software integration, the creation of standard interfaces that would allow manufacturers of different systems to interconnect their equipment and the creation of a model that would be used world-wide. There are seven layers to the OSI. The lowest - or first - layer allows a contiguous sequence of bits to be transmitted through the network. Which is the first layer: A. data-link layer, B. physical layer, C. network layer, D. transport layer
Computers and Technology
1 answer:
andrew-mc [135]3 years ago
6 0

Answer:

A. data-link layer

Explanation:

Data-link layer is the first layer and allows a contiguous sequence of bits to be transmitted through the network.

On top of it is the Network Layer and it handles the task of routing network messages from one computer to another.

Then comes the Transport Layer which is the basic layer at which one network computer communicates with another network computer.

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1 Lack of Preparation.

2 Poor Use of Visuals.

3 Inappropriate Humor.

4 Inappropriate Dress.

5 Not Knowing the Audience.

6 Non-Functioning Equipment.

7 Starting or Ending a Presentation Late.

8 Using a Monotone Voice.

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Create 3–5 questions about your data that can be answered by sorting and filtering the database.
My name is Ann [436]

Answer:

With the help of sorting and filtering techniques we can get answers of may question.

Explanation

For example, there is a database of a book shop, we create few questions from that database, to get answer with the help of sorting and filtering techniques.

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Gemiola [76]

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When installing a device driver, start the computer in
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Let A and B be two stations attempting to transmit on an Ethernet. Each has a steady queue of frames ready to send; A’s frames w
Mariana [72]

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete and correct question in the attachment file.  

For Point a:

For the second round,

A is selects kA(2)  either 0 or 1, so for each of them, that is \frac{1}{2}.

B selects kB(2)\  from\  (0, 1, 2, 3) for each choice with the probability of \frac{1}{4}.

If kA(2) < kB(2) wins the second rear race.

\to P[A \ wins] = P[kA(2) < kB(2)]

                     = P[kA(2) = 0] \times P[kB(2) > 0] + P[kA(2) = 1] \times P[kB(2) > 1]\\\\= \frac{1}{2} \times \frac{3}{4}  + \frac{1}{2}  \times \frac{2}{4} \\\\=\frac{3}{8}  +\frac{2}{8} \\\\= \frac{3+2}{8}\\\\= \frac{5}{8}

For Point b:

Throughout this example, kA(3) also selects to be either 0 or 1 with such a \frac{1}{2} probability. So, although B chooses kB(3) from (0, 1, 2, 3, 4, 5, 6, 7), the probabilities each are \frac{1}{8}:

\to P[A \  wins] = P[kA(3) < kB(3)]

                     = P[kA(3) = 0] \times P[kB(3) > 0] + P[kA(3) = 1] \times P[kB(3) > 1]\\\\= \frac{1}{2} \times \frac{7}{8} + \frac{1}{2} \times \frac{6}{8}\\\\= \frac{7}{16} + \frac{6}{16}\\\\= \frac{7+6}{16} \\\\= \frac{13}{16}\\\\

For point c:

Assume that B tries again 16 times (typical value), and it destroys. In addition, throughout the exponential background n is obtained at 10 when choosing k between 0 to 2n−1. The probability of A winning all 13 backoff events is: P[A \text{wins remaining races}] = 16\pi i =4P[A \ wins \ i |A \ wins \ i -1 ]

Let the k value kA(i) be A for the backoff race I select. Because A retains the breed

=(kA(i)] \cdot P[kA(i+ 1)< kB(i+ 1)] \geq P[kA(i) + 1

For point d:

Two stations A and B are supposed. They assume that B will try 16 times afterward. Even so, for A, 16 races were likely to also be won at a rate of 0.82 For Just higher expectations of three A, B, and C stations. For Station A, possibility to win all backoffs

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