Answer:
The answer to your question is 55.224 g of NiCl₂
Explanation:
I will solve it and then I compare the results.
Data
Volume = 0.8 l
Molarity = 0.531
substance = NiCl₂
Process
1.- Calculate the molar mass of NiCl₂
NiCl₂ = 59 + (35.5 x 2)
= 130 g
2.- Calculate the number of moles
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = 0.531 x 0.8
-Result
moles = 0.4248
3.- Convert the moles to mass
130 g -------------------- 1 mol of NiCl₂
x -------------------- 0.4248 moles
x = (0.4248 x 130) / 1
-Simplifying
x = 55.224 / 1
-Result
x = 55.224 g of NiCl₂
4.- We need 55.224 g of NiCl₂ to prepare 0.8l of a solution 0.531 M.
You have similar results, just our molar mass is different.
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