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Paul [167]
2 years ago
13

Calculating grams:

Chemistry
1 answer:
Alex_Xolod [135]2 years ago
6 0

Answer:

The answer to your question is 55.224 g of NiCl₂

Explanation:

I will solve it and then I compare the results.

Data

Volume = 0.8 l

Molarity = 0.531

substance = NiCl₂

Process

1.- Calculate the molar mass of NiCl₂

NiCl₂ = 59 + (35.5 x 2)

         = 130 g

2.- Calculate the number of moles

Molarity = moles / volume

-Solve for moles

  moles = Molarity x volume

-Substitution

  moles = 0.531 x 0.8

-Result

  moles = 0.4248

3.- Convert the moles to mass

                   130 g -------------------- 1 mol of NiCl₂

                      x     -------------------- 0.4248 moles

                           x = (0.4248 x 130) / 1

-Simplifying

                         x = 55.224 / 1

-Result

                        x = 55.224 g of NiCl₂

4.- We need 55.224 g of NiCl₂ to prepare 0.8l of a solution 0.531 M.

You have similar results, just our molar mass is different.

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