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4 years ago

What property of liquid oxygen makes it especially difficult and potentially harmful to work with at home?

1 answer:

3 0

The property of liquid oxygen that makes it especially difficult and potentially harmful to work with at home would be its cryogenic temperature. Liquid oxygen is being produced from the compression of oxygen gas to -196 degrees Celsius. As you can see, it has a very cold temperature that is why it used in cryogenics. Although liquid oxygen is non-toxic to humans, it would cause burns that are severe when being touched. Also, it would make certain materials brittle and unstable. Another property that makes it dangerous for use at home would be that it is very flammable. Proper handling is a must for this substance.

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What is the maximum number of grams of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl

Genrish500 [490]

<u>Answer:</u> The maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

Molarity of p-toluidine hydrochloride solution = 0.167 M

Volume of solution = 70. mL

Putting values in above equation, we get:

$0.167M=\frac{\text{Moles of p-toluidine hydrochloride}\times 1000}{70}\\\\\text{Moles of p-toluidine hydrochloride}=\frac{0.167\times 70}{1000}=0.0117mol$

The chemical equation for the reaction of p-toluidine hydrochloride and acetic anhydride follows:

$\text{p-toluidine hydrochloride}+\text{Acetic anhydride}\rightarrow \text{N-acetyl-p-toluidine}$

By Stoichiometry of the reaction:

1 mole of p-toluidine hydrochloride produces 1 mole of N-acetyl-p-toluidine

So, 0.0117 moles of p-toluidine hydrochloride will produce = $\frac{1}{1}\times 0.0117=0.0117mol$ of N-acetyl-p-toluidine

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of N-acetyl-p-toluidine = 149.2 g/mol

Moles of N-acetyl-p-toluidine = 0.0117 moles

Putting values in equation 1, we get:

$0.0117mol=\frac{\text{Mass of N-acetyl-p-toluidine}}{149.2g/mol}\\\\\text{Mass of N-acetyl-p-toluidine}=(0.0117g/mol\times 149.2)=1.7g$

Hence, the maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.

6 0

4 years ago

A certain metal hydroxide, m(oh)2, contains 32.8% oxygen by mass. what is the identity of the metal m? enter the full name of th

Simora [160]

Solution:[tex]Let the molar mass of metal M is 'a',\\ \rn(so)\\ \frac{M_{o}}{2M_{H}+2M_{o}+a} =\frac{2.16}{2.1+2.16+a} =0.328\\ By simple algebric calculation. We get,\\ a=63.56g/mol\\ \rn(Now,)\\

We have to confirm which metal has the molar mass of 63.56g/mol. By using periodic table we have to find it the we get it is Copper(Cu).

8 0

3 years ago

Are kilograms heavy?

Softa [21]

Answer:

yes

Explanation:

6 0

3 years ago

Read 2 more answers

The element chlorine (Cl) has 17 protons and 17 electrons. What happens to an atom of chlorine (Cl) if it gains an electron?

Vesna [10]

Answer:

It becomes negatively charged

Explanation:

An atom of chlorine having equal number of protons and electrons is neutral. The protons are the positively charged particles located in the nucleus of an atom. Electrons are negatively charged particles located outside the nucleus.

When the number of electrons and protons are the same, such an atom is neutral.

If the number of protons is more, the atom becomes positively charged.

In this case, the atom adds or gains an electron making the number of electrons to go from 17 to 18. This is more than the number of protons which are 17 by 1. The charge on the atom is therefore -1.

4 0

3 years ago

Read 2 more answers

In the reaction ca + f2 caf2 , what should be the coefficient for f2?

alex41 [277]

Answer : In the reaction of Ca + $F _{2}$ --->Ca $F _{2}$ , the coefficient of Ca and $F _{2}$ will be the same which will be 1.

Explanation : As per the rules of writing a chemical equation and balancing it properly, the number of elements in reactants side should be equal to the number of elements generated in product side. Hence when we use 1 molecule of Ca and one molecule of $F _{2}$ then it generates 1 molecule of Ca $F _{2}$ .

6 0

3 years ago