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katrin [286]
3 years ago
10

Expand and combine like terms. (4b^2+3)(4b^2-3)

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:

16b^4-9

Step-by-step explanation:

Factoring gives us 16b^4+12b^2-12^2-9. Simplifying gives us the answer which is 16b^4-9

Dahasolnce [82]3 years ago
6 0

Answer:

16b^4-9

Step-by-step explanation:

When multiplying binomials, we can use a method called FOIL (First-Outside-Inside-Last).

For (t_1+t_2)(t_3+t_4), let:

t_1\implies \text{First Term},\\t_2\implies \text{Second Term},\\t_3\implies \text{Third Term},\\t_4\implies \text{Fourth Term}

In the FOIL method, the steps go:

\text{\textbf{F}irst: Multiply the first and third terms (first term of each binomial)},\\\text{\textbf{O}utside: Multiply the first and fourth terms},\\\text{\textbf{I}nside: Multiply the second and third terms},\\\text{\textbf{L}ast: Multiply the second and fourth terms (last term of each binomial) }

Given (4b^2+3)(4b^2-3), we have:

\text{First: }4b^2\cdot 4b^2,\\\text{Outside: }4b^2\cdot -3,\\\text{Inside: }3\cdot 4b^2,\\\text{Last: }3\cdot -3,\\\rightarrow 16b^4-12b^2+12b^2-9

Combine like terms:

\boxed{16b^4-9}

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