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katrin [286]
2 years ago
10

Expand and combine like terms. (4b^2+3)(4b^2-3)

Mathematics
2 answers:
vaieri [72.5K]2 years ago
7 0

Answer:

16b^4-9

Step-by-step explanation:

Factoring gives us 16b^4+12b^2-12^2-9. Simplifying gives us the answer which is 16b^4-9

Dahasolnce [82]2 years ago
6 0

Answer:

16b^4-9

Step-by-step explanation:

When multiplying binomials, we can use a method called FOIL (First-Outside-Inside-Last).

For (t_1+t_2)(t_3+t_4), let:

t_1\implies \text{First Term},\\t_2\implies \text{Second Term},\\t_3\implies \text{Third Term},\\t_4\implies \text{Fourth Term}

In the FOIL method, the steps go:

\text{\textbf{F}irst: Multiply the first and third terms (first term of each binomial)},\\\text{\textbf{O}utside: Multiply the first and fourth terms},\\\text{\textbf{I}nside: Multiply the second and third terms},\\\text{\textbf{L}ast: Multiply the second and fourth terms (last term of each binomial) }

Given (4b^2+3)(4b^2-3), we have:

\text{First: }4b^2\cdot 4b^2,\\\text{Outside: }4b^2\cdot -3,\\\text{Inside: }3\cdot 4b^2,\\\text{Last: }3\cdot -3,\\\rightarrow 16b^4-12b^2+12b^2-9

Combine like terms:

\boxed{16b^4-9}

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You are creating an open top box with a piece of cardboard that is 16 x 30“. What size of square should be cut out of each corne
Arada [10]

Answer:

\frac{10}{3} \ inches of square should be cut out of each corner to create a box with the largest volume.

Step-by-step explanation:

Given: Dimension of cardboard= 16 x 30“.

As per the dimension given, we know Lenght is 30 inches and width is 16 inches. Also the cardboard has 4 corners which should be cut out.

Lets assume the cut out size of each corner be "x".

∴ Size of cardboard after 4 corner will be cut out is:

Length (l)= 30-2x

Width (w)= 16-2x

Height (h)= x

Now, finding the volume of box after 4 corner been cut out.

Formula; Volume (v)= l\times w\times h

Volume(v)= (30-2x)\times (16-2x)\times x

Using distributive property of multiplication

⇒ Volume(v)= 4x^{3} -92x^{2} +480x

Next using differentiative method to find box largest volume, we will have \frac{dv}{dx}= 0

\frac{d (4x^{3} -92x^{2} +480x)}{dx} = \frac{dv}{dx}

Differentiating the value

⇒\frac{dv}{dx} = 12x^{2} -184x+480

taking out 12 as common in the equation and subtituting the value.

⇒ 0= 12(x^{2} -\frac{46x}{3} +40)

solving quadratic equation inside the parenthesis.

⇒12(x^{2} -12x-\frac{10x}{x} +40)=0

Dividing 12 on both side

⇒[x(x-12)-\frac{10}{3} (x-12)]= 0

We can again take common as (x-12).

⇒ x(x-12)[x-\frac{10}{3} ]=0

∴(x-\frac{10}{3} ) (x-12)= 0

We have two value for x, which is 12 and \frac{10}{3}

12 is invalid as, w= (16-2x)= 16-2\times 12

∴ 24 inches can not be cut out of 16 inches width.

Hence, the cut out size from cardboard is \frac{10}{3}\ inches

Now, subtituting the value of x to find volume of the box.

Volume(v)= (30-2x)\times (16-2x)\times x

⇒ Volume(v)= (30-2\times \frac{10}{3} )\times (16-2\times \frac{10}{3})\times \frac{10}{3}

⇒ Volume(v)= (30-\frac{20}{3} ) (16-\frac{20}{3}) (\frac{10}{3} )

∴  Volume(v)= 725.93 inches³

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Answer:

f(2) = -2 + 12 = 10 so the ordered pair is (-2, 10).

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