what is the probability of drawing two yellow marbles if the first on is NOT place back into the bag before the second draw?

Mathematics

1 answer:

Kruka [31]3 years ago

6 0

Answer:

1/45

Step-by-step explanation:

I assume there are 10 marbles total, 2 of which are yellow.

The probability the first marble is yellow is 2/10.

There's now one less marble, so the probability that the second marble is yellow is 1/9.

The total probability is (2/10) (1/9) = 1/45.

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Oliga [24]

Answer:

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Step-by-step explanation:

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* The above answer is written in reverse, which is the exact same result.

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3 years ago

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Sergio039 [100]

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2 years ago

For the following geometric sequence find the recursive formula: {-1, 3, -9, ...}.

vredina [299]

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$a_n$ is the nth term
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2 years ago

An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con

natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

$L = 3w --- (1)volume = l \times w \times h \\ \\ 88 = (3w) \times w \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\$

The construction cost now is:

$C = 4(l \times w) + 2 ( w \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}$

Now, to determine the minimum cost:

$\dfrac{dC}{dw}= 0 \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}$