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3 years ago

Solve 4x+y=8 x+y=5 Solving by elimination

Mathematics

2 answers:

Arada [10]3 years ago

6 0

Step-by-step explanation:

4x+y=8

x+y=5

5(4x+y)=8

8(x+y)=5

20x+5y=40

8x+8y=40

2x_3y=0

2×_3y

Ulleksa [173]3 years ago

3 0

Answer:

y=4,x=1

Step-by-step explanation:

4x+y=8

x+y=5

subtract equation 2 from equation 1

3x + 0=3

3x=3

divide both sides by 3

x=1

substitute for x=1 in equation 2

x+y=5

1+y=5

y=5-1(collecting like terms)

y=4

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2 years ago

Find the value of x which satisfies the following equation. log2(x−1)+log2(x+5)=4

weqwewe [10]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: x = 3$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: log_{2}(x - 1) log_{2}(x + 5) = 4$

$\qquad \tt \rightarrow \: log_{2} \{(x - 1)(x + 5) \} = 4$

[ log (x) + log (y) = log (xy) ]

$\qquad \tt \rightarrow \: ( x - 1)(x + 5) = {2}^{4}$

$\qquad \tt \rightarrow \: {x}^{2} + 5x - x - 5 = 16$

$\qquad \tt \rightarrow \: {x}^{2} + 4x - 5 - 16 = 0$

$\qquad \tt \rightarrow \: {x}^{2} + 4x -21 = 0$

$\qquad \tt \rightarrow \: {x}^{2} + 7x - 3x - 21 = 0$

$\qquad \tt \rightarrow \: x(x + 7) - 3(x + 7) = 0$

$\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0$

$\qquad \tt \rightarrow \: x = - 7 \: \: or \: \: x = 3$

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

$\qquad \tt \rightarrow \: x = 3$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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2 years ago