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3 years ago

7

Depreciation is the decrease in value of an item. Three years ago, Aaron bought a computer for $930. The computer is now worth $

570. Assuming the value of the computer depreciates linearly, what is its yearly depreciation?

1 answer:

Umnica [9.8K]3 years ago

7 0

Answer:

$120

Step-by-step explanation:

930-570=360 (Price difference in 3 years)

360 divided by 3= 120 (Price difference for each of the 3 years)

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Oksana_A [137]

Answer: -4

Reasoning: so first you need to subtract the 7 from the 9 to get -2. Then you square it to get 4 because a negative 2 times -2 is 4. Then you multiply the 4 by the 2 to get 8. You can simplify the -10/5 to -1/2 and multiply that by the 8 to get -8/2 which simplified out to -4.

I hope that helps.

8 0

3 years ago

Read 2 more answers

What is the slope of the line?

Valentin [98]

(1 , -3)
(-3, 4)
Y2-y1/x2-x1
4 - -3 / -3 - 1
-7/ -4
Your slope is -1.75
Hope this helps *smiles*

4 0

3 years ago

Read 2 more answers

Graph the function f(x) = x3 – 5x2 + 6x using the graphing calculator. What are the solutions to the related equation? Check all

Juli2301 [7.4K]

the solutions to the related equation are 0,2,3 .

<u>Step-by-step explanation:</u>

Here we have , function f(x) = x3 – 5x2 + 6x . Graph of this function is given below . We need to find What are the solutions to the related equation . Let's find out:

Solution of graph means the value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !

At x = 0 .

From the graph , at x=0 we have f(x) = 0 i.e.

⇒ $f(x) = x^3- 5x^2 + 6x$

⇒ $f(0) = 0^3- 5(0)^2 + 6(0)$

⇒ $f(0) =0$

At x = 2 .

From the graph , at x=2 we have f(x) = 0 i.e.

⇒ $f(x) = x^3- 5x^2 + 6x$

⇒ $f(0) = 2^3- 5(2)^2 + 6(2)$

⇒ $f(0) =0$

At x=3 .

From the graph , at x=3 we have f(x) = 0 i.e.

⇒ $f(x) = x^3- 5x^2 + 6x$

⇒ $f(0) = 3^3- 5(3)^2 + 6(3)$

⇒ $f(0) =0$

Therefore , the solutions to the related equation are 0,2,3 .

3 0

4 years ago

The area of the triangle below is 10.6 square centimeters. What is the length of the

CaHeK987 [17]

Answer:

6 cm

Step-by-step explanation:

The area of a triangle is $\frac{bh}{2} = A$ , where b = base, h = height, and A = area. In this case, we're given the height as 4 cm and the area as 6 cm^2.

Let's plug in these values.

$\frac{4b}{2} = 6$

Now, let's solve this algebraically.

Step 1: Multiply both sides by 2.

$\frac{4b}{2} * 2 = 6 * 2$
$4b = 12$

Step 2: Divide both sides by 4.

$\frac{4b}{4} = \frac{12}{4}$
$b = 3$

Step 3: Check if solution is correct.

$\frac{3*4}{2} = 6$
$\frac{12}{2} = 6$
$6 = 6$

Therefore, the base is 6 cm. (but don't put the cm in the box because it's already there)

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0

3 years ago

Write the exact value of the side length of each square. If the value is not a whole number, estimate the length.

Savatey [412]

Given:

The area of the squares are given.

To find:

The exact side length or estimate side length of the square.

Solution:

We know that, the area of a square is

$A=a^2$

Where, a is the side length of the square.

$a=\sqrt{A}$

Area of the square is 100 square units. So, the side length is:

$a=\sqrt{100}$

$a=10$

Therefore, the side length is 10 units.

Area of the square is 95 square units. So, the side length is:

$a=\sqrt{95}$

It is not exact. We know that $\sqrt{81}$ .

Therefore, the side length is between 9 and 10.

Area of the square is 36 square units. So, the side length is:

$a=\sqrt{36}$

$a=6$

Therefore, the side length is 6 units.

Area of the square is 30 square units. So, the side length is:

$a=\sqrt{30}$

It is not exact. We know that $\sqrt{25}$ .

Therefore, the side length is between 5 and 6.

8 0

3 years ago