Proof:
3 consecutive integers are x, x+1 , x+2.
Add these values.
x+x+1+x+2
3x+3
3×(x+1)
3(x+1) is the multiple of 3 for any integer value of x.
Answer:
A. because it doesn't change as it is going up, up, up, and so on.
You would have to make the numbers have the same denominator. So you would have -15/20 + 4/20
Then you would have to put the sign of the higher number on it, So you would have -15/20 + 4/20 = -11/20
Add 2 to 3 and get 5 add 3 and get 8 add 5 to get 13 add 8 to get 21
