The points Q(-1,1),R(2,-3), and S(-1,-3) are the vertices of a triangle. Find the area of the triangle
1 answer:
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Answer:
10y = 13x + 139
Step-by-step explanation:
Points (-5, -3) and (-15, -16) are the two points through which Line 1 passes.
So, the slope of the line 1 is
Now, the slope of the parallel straight line i.e. line 2 will be same as line 1 i.e.
Let us assume that the equation of line 2 is
{Where c is a constant} ....... (1)
Now, line 2 passes through the point (-13, 17). Hence, this point will satisfy equation (1).
So,
⇒
Therefore, the equation of line 2 will be
⇒ 10y = 13x + 139 (Answer)