54000/.6= 90000, so answer should be 90,000
Answer:
You can plug it into a graphing website or calculator to double check
Answer:
B
Step-by-step explanation:
The explicit rule for a geometric sequence is
= a₁ 
where a₁ is the first term and r the common ratio
Here a₁ = 64 and r = 
= 
= 2 , then
= 64 
→ B
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
Answer:
3 meters
Step-by-step explanation:
We assume the storage room is a rectangle, like most rooms, no indication it is otherwise.
We know it's a rectangle and not a square because it is longer than wide.
We have the perimeter measurement (16 meters).
So, we can make the following equation:
2x + 2y = 16
x being the width of the room, y being it's length. A perimeter is the sum of all sides.
We also know the room is 2 meters longer than wide... so:
y = x + 2
If we replace y in the first equation by its value relative to x, we get:
2x + 2(x + 2) = 16 which becomes
2x + 2x + 4 = 16
4x =12
thus x = 3
Width: 3 meters
Length: 5 meters.
Confirms the 16 meters perimeter.
