Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
<span><span>d/<span>dx</span></span><span>[<span><span>10x</span>+<span>e2</span></span>]
</span></span><span>=<span><span><span>d/<span>dx</span></span><span>[<span>10x</span>]</span></span>+<span><span>d/<span>dx</span></span><span>[<span>e2}
</span></span></span></span></span><span>=<span>ln<span>(10)</span></span>⋅<span>10x</span>+0
</span><span>=ln<span>(10)</span>⋅<span>10<span>x</span></span></span>
we need some barriers such that total of length of all barriers should equal to the circumference of the circle.
so lets assume we need x barriers
then total length of all barriers = 2.5x meter
now radius of circular path = diameter / 2= 13/2 = 6.5 meter
circumference of path = 2× pi × r = 2 × 3.14 × 6.5
=40.82 meter
so now as per statement
2.5x = 40.82
x = 40.82/2.5 = 16.328 ≈ 17
so approximately 17 barriers are required
Hey there! :D
The tenth place is where the first 6 is, so:
1.666666666667=
1.7 because 6>5
I hope this helps!
~kaikers
Answer:
up to 5 candy bars
Step-by-step explanation:
