Answer:
1/4
Step-by-step explanation:
hope it helped
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There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Solution:</u></h3>
Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
I believe the answers are c and d
Answer:
I can help with Q "4" as -
It uses triangle congruence test - here we use - SAS, as
one side is equal as it is given
both the angles are 90 degree
and they share a same side
so -
8x = 6x + 5
8x - 6x = 5
2x = 5
x = 2.5
RU = 6x+ 5 = 6 (2.5) + 5 = 20
( I am not so sure but I think this is the answer )