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Mariana [72]
3 years ago
4

The graph of the equation y = ax2 is shown

Mathematics
1 answer:
madam [21]3 years ago
5 0

Answer:

The graph of the new equation is y = -5ax^2

Step-by-step explanation:

From the question, the graph of the equation is y= ax^2

Now, multiplying a by -5, the graph of the new equation will be (-5 *a)x^2

The graph of the new equation is thus y = -5ax^2

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What is 325 divided by 6344
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A landscaper has a total of $800 to spend on bushes at $20 each and trees at $50 each
NemiM [27]

Answer:

x=40 y=16

Step-by-step explanation:

20x+50y=800 you can turn it into slope-intercept form and it would end up being y=-2/3x+16 so now you have your y intercept (16) and you know your rise and run -2(rise)3(run).

Or you can substitute a zero for x and solve for y

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4 years ago
At a costumer service call center for a large company, the number of calls received per hour is normally distributed with a mean
Marysya12 [62]

We have been given that at a customer service call center for a large company, the number of calls received per hour is normally distributed with a mean of 150 calls and a standard deviation of 5 calls. We are asked to find the probability that during a given hour of the day there will be between 146 calls and 163 calls.

First of all, we will use z-score formula to find z-score corresponding to 146 and 163.

z=\frac{x-\mu}{\sigma}

z=\frac{146-150}{5}

z=\frac{-4}{5}

z=-0.8

z=\frac{163-150}{5}

z=\frac{13}{5}

z=2.6

Our next step is to find percentage of data scores falls between both z-scores.

P(-0.8

Using normal distribution table, we will get:

P(-0.8

P(-0.8

Let us convert our answer into percentage.

0.78348\times 100\%=78.348\%

Upon rounding our answer to nearest thousandths, we will get:

78.348\%\approx 78.35\%

Therefore, the probability that during a given hour of the day there will be between 146 calls and 163 calls is approximately 78.35\%.

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Answer:

Step-by-step explanation:

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3 years ago
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