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olga_2 [115]
3 years ago
9

. Harold works at a men's clothing store, which marks up its retail clothing by 27%. The store purchases pants for $74.00, suit

jackets for $325.00, and dress shirts for $48.00. How much is the markup for a pair of pants, a dress shirt, and a suit jacket?
Mathematics
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

567.69

Step-by-step explanation:

Let p represent the original price

The Mark up is 27%

= 27/100

= 0.27

= p + 0.27p

= 1.27p

The retail price for pants is

= 1.27(74)

= 93.98

The retail price for suit jacket is

= 1.27(325)

= 412.75

The retail price for dress shirt is

= 1.27(48)

= 60.96

Therefore the markup for a pair of pants, dress shirts and suit jacket can be calculated as follows

= 93.98 + 412.75 + 60.96

= 567.69

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The angle measures associated with which set of ordered pairs share the same reference angle? (Negative StartFraction StartRoot
Katarina [22]

Answer:

(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)

Step-by-step explanation:

The reference angle is the angle that the given angle makes with the x-axis.

For an ordered pair to share the same reference angle, the x and y coordinates must be the same or a factor of each other.

From the given options:

(A)\left(-\dfrac{\sqrt{3} }{2} ,-\dfrac{1 }{2}\right)$ and \left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)\\\\(B)\left(\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(-\dfrac{\sqrt{3} }{2}, \dfrac{1 }{2}\right)\\\\(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)\\\\(D)\left(\dfrac{\sqrt{3} }{2},\dfrac{1 }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)

We observe that only the pair in option C has the same x and y coordinate with the second set of points being a negative factor of the first term. Therefore, they have the same reference angle.

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3 years ago
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7/8y + 1/2 = 1 1/5<br><br> Solve for y.
abruzzese [7]

Answer:

y = 4/5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

7/8y + 1/2 = 1 1/5

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Convert to improper fraction:                                                                          7/8y + 1/2 = 6/5
  2. [Subtraction Property of Equality] Subtract 1/2 on both sides:                       7/8y = 7/10
  3. [Division Property of Equality] Divide 7/8 on both sides:                              y = 4/5
3 0
3 years ago
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