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Oxana [17]
3 years ago
11

Answer this for me please and quick!!​

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0
0.90 x 27 = 24.3

you can multiply or put it in a proportion
iren2701 [21]3 years ago
3 0

Answer:

24.3

Step-by-step explanation:

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marishachu [46]

Answer: it’s B

Step-by-step explanation:

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How do i write b + 3 = b^2 in verbal expression
igor_vitrenko [27]

Answer:

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3 years ago
The J.O. Supplies Company buys calculators from a non-US supplier. The probability of a defective calculator is 10 percent. If 3
RSB [31]

Answer:

There is a 24.3% probability that one of the calculators will be defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability of a defective calculator is 10 percent.

This means that p = 0.1

If 3 calculators are selected at random, what is the probability that one of the calculators will be defective

This is P(X = 1) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.1)^{3}.(0.9)^{2} = 0.243

There is a 24.3% probability that one of the calculators will be defective.

3 0
3 years ago
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