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3 years ago

Help me with 2a and 2b please

Mathematics

1 answer:

Vaselesa [24]3 years ago

3 0

Answer:

Step-by-step explanation:

A∩B={x| x∈a and x∈B}

a) A∩B={4,6}

b) A∩B={ 4,9}

c) A∩B={yellow,green}

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She made 3.41 in commission.

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4 years ago

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The weekly sales of Honolulu Red Oranges is given by q = 990 − 22p. Calculate the price elasticity of demand when the price is $

elena55 [62]

Answer:

E = -2. The demand is going down by 2% per 1% increase in price at that price level.

The price that gives a maximum revenue is $22.5. The maximum revenue is $9112.5

Step-by-step explanation:

The overall demand formula: Q = aP + b

Q = 990 - 22P

<u>Demand elasticity:</u>

At P = $30, the Q = 990 - 22×30 = 330. a = $\frac{dQ}{dP}$ = -22

The formula for demand elasticity: E = $\frac{dQ}{dP}$ × $\frac{P}{Q}$

Demand elasticity at $30: E = -22 × $\frac{30}{330}$ = -2

So, The demand will be going down by 2% if 1% increase in price.

<u>Revenue:</u>

R = P×Q = P×(990 - 22P) = -22P² - 990P

R' = -44P - 990. The revenue is maximum when R' = 0

⇔0 = -44P - 990 ⇔ P = $22.5

At the P = $22.5, the Q = 990 - 22×22.5 = 495.

The maximum revenue = $22.5×495 = $11,137.5

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3 years ago

What is 1/8+1/4-14 equal what

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= 3/8-14

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I hope that's help !

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3 years ago

How are yards and feet related

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3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

4 years ago