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2 years ago

Bananas are .95/1 pound, what is the constant of proportionality?

Mathematics

1 answer:

Sidana [21]2 years ago

7 0

Since y is .95 and x is 1 it is a unit rate which is the constant of proportionality.

Correct me if I am wrong.

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Which of the following could be a function with zeros of —3 and 2? А f(x) = (x - 3)(x + 2) B f(x) = (x = 3)(x - 2) © f(x) = (x+3

Zinaida [17]

Answer:

Step-by-step explanation:

to find the zeros you look at what value you would fill in for x to make zero, so (x+3) would have a zero of -3 and (x-2) would have a zero of 2

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2 years ago

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7.50 times hours would be her pay then add the bonus x number of bouquets

a = 7.50h +(bn)

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2 years ago

What is 18% of 50? _90 _50 _36 _9 _18

FrozenT [24]

Answer:

Step-by-step explanation:

percentages are reversable. like instead of 18% of 50 you could reverse it and say what is 50% of 18. which is 9.

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2 years ago

Read 2 more answers

Look at the bottom of the pictures to see what number it is

kondaur [170]

Step-by-step explanation:

hence the value of y=-9/4and k=-16.

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2 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0

2 years ago