What is the best estamate of 0.06534
1 answer:
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Answer:
The artist should make 15 caricatures and 30 portraits.
Step-by-step explanation:
First, we identify the variables for the problem. In this case, the variables will be:
C=number of caricatures
P= number of portraits.
Next, we can use the variables to make the inequalities that constrain the problem.
We know the artist can't spend more than $360 for supplies and we also know that it costs $4 to make a caricature and $10 to make a portrait, so:
We also know the artist has a limit of time of 20 hours, which is the same as 20*60=1200 minutes to paint. We know it takes her 20 minutes to make a caricature and 30 minutes to make a portrait, so:
and we also know she must make a positive number of caricatures and a positive number of portraits so the other two constrains are:
So we can go ahead and graph them. (see attached picture)
Once we graphed the inequalities we can determine what the corners of the polygon created by the intersection of the shaded areas are, so we proceed and calculate them:
first point:
(0,0)
second point:
4(0)+10P=360
P=36
(0,36)
Third point:
20C+30(0)=1200
C=60
(60,0)
Fourth point:
We multiply the first equation by -5 so we get:
-20C-50P=-1800
20C+30P=1200
------------------------
-20P=-600
P=30
so:
20C+30(30)=1200
20C=1200-900
20C=300
C=15
(15,30)
Once we found the 4 points, we go ahead and evaluate them for the objective function. In this case, the objective function is the total amount of money she got from selling the pieces of art, so we get:
I=10C+20P
Point 1
I=10(0)+20(0)=0
Point 2
I=10(0)+20(36)=720
Point 3
I=10(60)+20(0)=600
Point 4
I=10(15)+20(30)=750
Next, we look for the greatest income which in this case will be 750 so that's why she must make 15 caricatures and 30 Portraits.
Answer:
The degrees of freedom are given by:
Now we can calculate the p value with the following probability:
And for this case since the p value is lower compared to the significance level we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05
Step-by-step explanation:
For this case we have the following info given:
represent the sample mean
represent the sample deviation
represent the reference value to test.
represent the sample size selected
The statistic for this case is given by:
And replacing we got:
The degrees of freedom are given by:
Now we can calculate the p value with the following probability:
And for this case since the p value is lower compared to the significance level we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05