S= savings before she bought the dress s - $55 would be her new balance after she bought the dress.
We could also talk about her savings now (after her purchase). If we let n=now
n + $55 would be her balance before she bought the dress.
Answer:
Sian would receive 20 Pounds while Abigail would receive 10 Pounds.
Step-by-step explanation:
Given that Sian is twice as old as her sister Abigail, it means that if Abigail's age is T years then Sian's age would be 2T years.
If they divide 30 pounds in the ratio of their ages, the ratio of their ages will be
T : 2T (Ratio of Abigail's gae to Sian's age)
The amount received by Abigail
= T/(T + 2T) × 30
= T/3T × 30
= 1/3 × 30
= 10 Pounds
The amount received by Sian
= 2T/(T + 2T) × 30
= 2T/3T × 30
= 2/3 × 30
= 20 Pounds
<u>Answer:</u>
The number of tickets bought is 1000 adults tickets and 700 children were present
<u>Explanation:</u>
Let the number of children and adults present in the circus be x and y respectively
According to question,
Then, x + y = 1700 ……………..equation (1)
And, cost of ticket to circus for children and adult be 19, 42 respectively
Total cost of ticket;
for adults = 42y; for children = 19x
19x + 42y = 55300 …………………equation (2)
Multiplying equation (1) by 19
19x + 19y = 32300 ……………… eqn (3)
Subtracting equation 1 and 3, we get
23y = 23000
y = 1000
putting this value in eq (1), we get x = 700
Therefore, 1000 adults and 700 children were present
.
Answer:
33+12t−21t^2
Step-by-step explanation:
(2t-7)²-(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².
4t^2−28t+49−(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².
4t^2−28t+49−(25t^2−40t+16)
To find the opposite of 25t^2
−40t+16, find the opposite of each term.
4t^2−28t+49−25t^2−40t+16
Combine 4t^2 and −25t^2 to get −21t^2.
−21t^2−28t+49+40t−16
Combine −28t and 40t to get 12t.
−21t^2+12t+49−16
Subtract 16 from 49 to get 33.
−21t^2+12t+33
Swap terms to the left side.
33+12t−21t^2
I hope this helped!
