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Naddika [18.5K]
3 years ago
6

Please help me with mathematics

Mathematics
1 answer:
klasskru [66]3 years ago
6 0

Answer:8

Step-by-step explanation:if im wrong sorry

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1. Divide
BartSMP [9]

Answer:

656×756÷765+656+65=

Step-by-step explanation:

it was soo easy now i get what it is talking about no

6 0
3 years ago
226Ra has a half-life of 1599 years. How much is left after 1000 years if the initial amount was 10 g?
Ray Of Light [21]
\bf \textit{Amount for Exponential Decay using Half-Life}\\\\
A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &10\\
t=\textit{elapsed time}\to &1000\\
h=\textit{half-life}\to &1599
\end{cases}
\\\\\\
A=10\left( \frac{1}{2} \right)^{\frac{1000}{1599}}
8 0
3 years ago
The temperature when Spencer arrived at school was a very chilly
dolphi86 [110]

Answer is 13°F

Step-by-step explanation:

3 0
3 years ago
Is (x+1) a factor off (x)=x3+x2−4x−4? <br><br> A) Yes<br> B) No
satela [25.4K]

Remainder theorem again...

p(x)=x^3+x^2-4x-4

p(-1)=(-1)^3+(-1)^2-4(-1)-4=0

So Yes, x+1 is a factor.

4 0
3 years ago
Read 2 more answers
$1500 is invested at a rate of 3% compounded monthly. Write a compound interest function to model this situation. Then find the
Marianna [84]

Answer:

<u>Equation</u>:  F=1500(1.0025)^{12t}

<u>The balance after 5 years is:  $1742.43</u>

<u></u>

Step-by-step explanation:

This is a compound growth problem . THe formula is:

F=P(1+\frac{r}{n})^{nt}

Where

F is future amount

P is present amount

r is rate of interest, annually

n is the number of compounding per year

t is the time in years

Given:

P = 1500

r = 0.03

n = 12 (compounded monthly means 12 times a year)

The compound interest formula modelled by the variables is:

F=1500(1+\frac{0.03}{12})^{12t}\\F=1500(1.0025)^{12t}

Now, we want balance after 5 years, so t = 5, substituting, we get:

F=1500(1.0025)^{12t}\\F=1500(1.0025)^{12*5}\\F=1500(1.0025)^{60}\\F=1742.43

<u>The balance after 5 years is:  $1742.43</u>

3 0
3 years ago
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