All categories

3 years ago

Write 63 as a sum of tens and ones

Mathematics

1 answer:

Ede4ka [16]3 years ago

4 0

6 tens and 3 ones=
60+3=63

You might be interested in

Please help this is due today! geometry

sdas [7]

Please mark brainliest

Answer is 4 units

Explanation:

See the image as mathematical signs can’t be written here

7 0

3 years ago

Lorena's backpack has te mad of 3,000 grams. What is the mass of Lorena's backpack in kilograms

Vinvika [58]

3 kilograms because 1,000 grams is equal to 1 kilogram

7 0

3 years ago

Read 2 more answers

17<br><br> i already did the test

Dmitry [639]

Answer:

Step-by-step explanation:

I believe the answer is 17.

Simplify

=17

Now,

Consider point O at zero on the number line.

Mark a point A such at number 4 such that OA= 4

Draw a perpendicular AB at point A of unit length.

Join AB

Taking radius of length AB draw an arc to intersect the number line at C.

Finally, OC=\sqrt{17}

Thus proving the answer is 17 or $\sqrt{289} = 17$

3 0

3 years ago

X squared - 5 + - 24

katovenus [111]

X² - 5 + -24

x² - 5 - 24

x² + (-5 - 24)

x² + 29

hope this helps, God bless!

4 0

3 years ago

Given the following linear function, sketch the graph of the function and find the domain and range.

Fantom [35]

1. To sketch the function f(x) = (2/3)x - 3, we first need to find two points that we can later join to sketch the line, for example the x- and y-intercepts.

a) The x-intercept occurs when f(x) = 0, so if f(x) = 0, then:

f(x) = (2/3)x - 3

0 = (2/3)x - 3

3 = (2/3)x (Add three to both sides)

3*(3/2) = x (Multiply both sides by 3/2)

9/2 = x

We have now found the x-intercept at (9/2, 0)

b) The y-intercept occurs when x = 0, so:

f(x) = (2/3)x - 3

f(0) = (2/3)*0 - 3

f(0) = -3

Now we know that the y-intercept is at (0, -3)

c) All that's left is to sketch the graph axes and label them, plot the two points, join them together using a ruler and label their coordinates.

2. The Domain is the range of x-values for which the function exists, and the Range is the range of y-values for which the function exists.

Since there haven't been any constraints specified, we can say that both the Domain and Range are (-∞, ∞), since the graph continues forever both along the x- and y-axis.

(Note that this isn't always the case and would change if, for example, the question stipulated that there was a domain of [0, 5] and you had to find the range. Then, you would calculate the value of y at each end of the domain (if x = 0, y = -3 and if x = 5, y = 1/3) - in my example, the range would thus be [-3, 1/3].)

7 0

3 years ago