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andrezito [222]
3 years ago
9

Dale mixed 5.9 grams of salt into a pot of soup he was cooking. Before he served the soup, Dale added 0.31 grams of salt. How mu

ch salt did Dale put into the soup in all? EXPLAIN what you need to do, and solve it. QUIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIICKKKKKKKKKKKKKKKKKKKKK
Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

<em>Dale put 6.21 grams of salt into the soup in all</em>

Step-by-step explanation:

<u>Arithmetic</u>

There are situations where different mathematic operations must be done in order to find the required results. Four operations are known as basics in arithmetic: addition, subtraction, multiplication, and division.

The question describes how Dale added 5.0 grams of salt into a pot of soup and then he added 0.31 grams of salt more. This means the total amount of salt added by Dale into the soup is the sum of both quantities:

Total salt added = 5.9 grams + 0.31 grams = 6.21 grams.

Dale put 6.21 grams of salt into the soup in all

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Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

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Step-by-step explanation:

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