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JulsSmile [24]
3 years ago
9

What percent of 45.4 is 6.81

Mathematics
1 answer:
Savatey [412]3 years ago
5 0
The awnser to this is 45%
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The amount 5th grade students grow during the school year is normally distributed with a mean of inches and a standard deviation
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Use the quadratic formula to solve the following equation -3x^2-x-3=0
tigry1 [53]

<u>Answer:</u>

x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i are two roots of equation -3 x^{2}-x-3=0

<u>Solution:</u>

Need to solve given equation using quadratic formula.

-3 x^{2}-x-3=0

General form of quadratic equation is a x^{2}+b x+c=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}

Since b^{2}-4 a c is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}

8 0
3 years ago
Given:
Ulleksa [173]

Triangle ASA's congruence theorems can be used in this ptoof

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2 years ago
the area of a rectangle is 2x^2-5-3 and the length of the rectangle is 2x+1. find the width of the rectangle​
ZanzabumX [31]

Answer:

x - 3

Step-by-step explanation:

\frac{2{x}^{2} - 5x - 3}{2x + 1} = \frac{[x - 3][2x + 1]}{2x + 1} = x - 3

This is much faster than doing long-polynomial division, which we could have done, since the divisor is not in the form of <em>x</em><em> </em><em>-</em><em> </em><em>c,</em><em> </em>where<em> </em><em>−</em><em>c</em><em> </em>gives gives the OPPOSITE TERMS OF WHAT THEY REALLY ARE.

I am joyous to assist you anytime.

3 0
3 years ago
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