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3 years ago

What percent of 45.4 is 6.81

Mathematics

1 answer:

Savatey [412]3 years ago

5 0

The awnser to this is 45%

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Day of a measles outbreak at a school, 8 students were identified to have the measles. Each day for the On the first following t

Mrrafil [7]

Answer:

D. 504

Step-by-step explanation:

Let the number of days = x

Now, the number of students doubles each day for the two weeks with the initial number of students having measles = 8.

So, we have,

Days (x) Cases doubled Number of Students

1 8 8

2 8 × 2 16

3 16 × 2 32

4 32 × 2 64

So, we get the geometric series as 8, 16, 32, 64,...... for two weeks.

Then, the common ratio = $\frac{16}{8}=\frac{32}{16}$ = 2

Thus, Number of students = $8\times \frac{(1-2^6)}{1-2}$

i.e. Number of students = $8\times \frac{(1-64)}{-1}$

i.e. Number of students = $8\times \frac{(-63)}{-1}$

i.e. Number of students = 8 × 63 = 504

Hence, the number of students having measles at the end of the 6th day are 504.

5 0

2 years ago

Read 2 more answers

The mean of six numbers is 45. Four of the numbers are 40, 38, 46, and 51. If the remaining two numbers are I. The ratio of 2:3,

Advocard [28]

Answer:

The numbers are 38 and 57

Step-by-step explanation:

Let

x-----> the missing smaller number

y----> the missing larger number

we know that

$45=\frac{40+38+46+51+x+y}{6} \\ \\270=175+x+y$

$x+y= 95$ -----> equation A

$\frac{x}{y}=\frac{2}{3}$

$x=\frac{2}{3}y$ -----> equation B

substitute equation B in equation A and solve for y

$\frac{2}{3}y+y= 95$

$\frac{5}{3}y= 95$

$y=95*3/5=57$

Find the value of x

$x=\frac{2}{3}(57)=38$

8 0

2 years ago

Answer This plz I need it <br> only answer if you know the answer and need the steps

FinnZ [79.3K]

Answer:

where is the picture

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I WILL GIVE BRAINLY

Gnom [1K]

9514 1404 393

Answer:

m^2 = 35/9

Step-by-step explanation:

The line will be tangent to the ellipse where there is one point of intersection between the line and the ellipse. We can find that case by looking at the discriminant of the quadratic.

x^2 +9(mx +2)^2 = 1

x^2 +9(m^2x^2 +4mx +4) = 1

(9m^2 +1)x^2+36mx +35 = 0 . . . . subtract 1, collect terms

Then the discriminant is ...

(36m)^2 -4(9m^2 +1)(35)

We want it to be zero, so we have ...

1296m^2 -1260m^2 -140 = 0 . . . . eliminate parentheses

36m^2 = 140 . . . . . . . . . . . . . . . add 140

m^2 = 140/36 . . . . . . . . . . . . divide by 36

m^2 = 35/9

3 0

2 years ago

Plz help! I’ll mark brainliest!

yan [13]

AE Should be Craig answer

6 0

2 years ago