One number is eight more than twice another. If their sum is decreased by nine, the result is fourteen. Find the numbers

1 answer:

6 0

$x-\ first \ number\\
y-\ second\ number\\\\
x-8=2y\\
x+y-9=14\\\\
x=2y+8\\
x+y=23\\\\
2y+8+y=23\\
3y+8=23\ \ \ |subtract\ 8\\
3y=15\ \ \ |divide\ by\ 3\\
y=5\\\\x=18$ Answer here

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