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Airida [17]
2 years ago
8

One number is eight more than twice another. If their sum is decreased by nine, the result is fourteen. Find the numbers

Mathematics
1 answer:
Oliga [24]2 years ago
6 0
x-\ first \ number\\
y-\ second\ number\\\\
x-8=2y\\
x+y-9=14\\\\
x=2y+8\\
x+y=23\\\\
2y+8+y=23\\
3y+8=23\ \ \ |subtract\ 8\\
3y=15\ \ \ |divide\ by\ 3\\
y=5\\\\x=18Answer here
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To solve this problem, first let x=0.933333(repeating). Then, you want to multiply both sides by 10 to get 10x = 9.33333 (repeating). Next, take equation 2 and minus equation 1 from it giving you 9x = 8.4. Finally, multiply both sides by 10 and you will get 90x = 84. Divide both sides by 90 giving x=84/90. Answer is 84/90. 84/90 can reduce to 14/15.

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