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Ratling [72]
4 years ago
12

Which of these is NOT a Pythagorean triple?

Mathematics
1 answer:
frozen [14]4 years ago
8 0
A=9+16=25  
B=36+64=100
C=25+144=169
D=64+1600=1681XxXxXx 
D is the answer becuase the pathagreiam theirum is A x^{2} +B x^{2} =C x^{2}

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What word describes the equal shares of the shape
marusya05 [52]
Parralel  or most likely symmetrical
8 0
3 years ago
A random sample of the actual weight of 5-lb bags of mulch produces a mean of 4.963 lb and a standard deviation of 0.067 lb. If
dsp73

Answer: B) 4.963±0.019.

Step-by-step explanation:

Confidence interval for population mean ( when population standard deviation is not given) is given by :-

\overline{x}\pm t^*\dfrac{s}{\sqrt{n}}

, where \overline{x} = Sample  mean

n= Sample size

s= sample standard deviation

t* = critical t-value.

As per given:

n= 50

Degree of freedom = n-1 =49

\overline{x}= 4.963\ lb

s= 0.067 lb

For df = 49 and significance level of 0.05 , the critical two-tailed t-value ( from t-distribution table) is 2.010.

Now , substitute all values in the formula , we get

4.963\pm (2.010)\dfrac{0.067}{\sqrt{50}}\\\\ 4.963\pm (2.010)(0.0094752)\\\\ 4.963\pm0.019045152\approx4.963\pm0.019

Hence,  a 95% confidence interval for the mean weight (in pounds) of the mulch produced by this company is 4.963\pm0.019.

Thus , the correct answer is B) 4.963±0.019.

7 0
3 years ago
A small publishing company is releasing a new book. The production costs will include a one-time fixed cost for editing and an a
Andrej [43]

Answer:

A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as editing) and variable costs (such as printing). The one-time fixed costs will amount to $17,750 . The variable costs will be $12.75 per book.

Step-by-step explanation:

7 0
3 years ago
For a test of population proportion H0: p = 0.50, the z test statistic equals 1.05. Use 3 decimal places. (a) What is the p-valu
sergiy2304 [10]

Answer:

(a) The <em>p</em>-value of the test statistic is 0.147.

(b) The <em>p</em>-value of the test statistic is 0.294.

(c) The <em>p</em>-value of the test statistic is 0.8531.

(d) None of the <em>p</em>-values give strong evidence against the null hypothesis.

Step-by-step explanation:

The <em>p</em>-value is well defined as the probability,[under the null hypothesis (H₀)], of attaining a result equivalent to or greater than what was the truly observed value of the test statistic.

We reject a hypothesis if the p-value of a statistic is lower than the level of significance <em>α</em>.

The null hypothesis for the test of population proportion is defined as:

<em>H₀</em>: <em>p</em> = 0.50

The value of <em>z</em>-test statistic is,

<em>z</em> = 1.05

(a)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> > 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value=P(Z>1.05)\\=1-P(Z

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.147.

(b)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> ≠ 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value=2\times P(Z>1.05)\\=2\times 0.1469\\=0.2938\\\approx 0.294

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.294.

(c)

The alternate hypothesis is defined as:

<em>Hₐ</em>: <em>p</em> < 0.50

Compute the <em>p</em>-value of the test statistic as follows:

p-value= P(Z1.05)=1- 0.1469\\=0.8531

*Use a <em>z</em>-table for the probability value.

Thus, the <em>p</em>-value of the test statistic is 0.8531.

(d)

The decision rule of the test is:

If the <em>p</em>-value of the test is less than the significance level <em>α</em>, then the null hypothesis is rejected at <em>α</em>% level of significance.

And if the <em>p</em>-value of the test is more than the significance level <em>α</em>, then the null hypothesis is failed to be rejected.

The most commonly used level of significance are:

<em>α</em> = 0.01, 0.05 and 0.10

The <em>p</em>-value for all the three alternate hypothesis are:

<em>p-</em>values = 0.147, 0.294 and 0.8531.

All the <em>p</em>-values are quite large compared to the <em>α</em> values.

Thus, none of the <em>p</em>-values give strong evidence against the null hypothesis.

The null hypothesis was failed to be rejected.

5 0
3 years ago
You are making numbers to hang outside the classrooms in your school.
Oksanka [162]

Answer:

0- 11 times

1,2,3,4,5,6,7,8,9- 12 times

5 0
3 years ago
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