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3 years ago

Solve the proportion 7/5=21/x

Mathematics

2 answers:

Paha777 [63]3 years ago

8 0

Answer:

Step-by-step explanation:

7/5=21/x

or, 7x=21*5

or, x=(21*5)/7

x=15

kondaur [170]3 years ago

3 0

Answer:

x=15

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

The volume of a cube is 8cm3, find the length of one of it's sides

Angelina_Jolie [31]

Answer:

The side length is 2 cm

Step-by-step explanation:

The volume of a cube is s^3

V = s^3

8 = s^3

Take the cube root of each side

8 ^ 1/3 = s^3 ^ 1/3

2 = s

The side length is 2 cm

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4 years ago

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Which division problem is represented with this model?

sp2606 [1]

D 1/6 % 2 is the correct answer

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3 years ago

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Simplify 81p6q2÷3p2q5 HELPPP

goldfiish [28.3K]

Answer:

$\displaystyle \frac{81\, p^{6}\, q^{2}}{3\, p^{2} \, q^{5}} = \frac{27\, p^{4}}{q^{3}}$ .

Step-by-step explanation:

Make use of the fact that for any $x \ne 0$ and integer $n$ :

$\displaystyle \frac{1}{x^{n}} = x^{-n}$ .

For example, in this question:

$\displaystyle \frac{1}{p^{2}} = p^{-2}$ .

$\displaystyle \frac{1}{q^{5}} = q^{-5}$ .

Thus, the original expression would be equivalent to:

$\begin{aligned}& \frac{81\, p^{6}\, q^{2}}{3\, p^{2} \, q^{5}} \\ =\; & \frac{81}{3}\, (p^{6}\, p^{-2})\, (q^{2}\, q^{-5}) \\ =\; & 27\, (p^{6}\, p^{-2})\, (q^{2}\, q^{-5})\end{aligned}$ .

Also make use of the fact that for any $x \ne 0$ , integer $m$ , and integer $n$ :

$x^{m}\, x^{n} = x^{m + n}$ .

Thus:

$\begin{aligned}& 27\, (p^{6}\, p^{-2})\, (q^{2}\, q^{-5}) \\=\; & 27\, p^{6 + (-2)}\, q^{2 + (-5)} \\ =\; & 27\, p^{4}\, q^{-3} \\ =\; & \frac{27\, p^{4}}{q^{3}}\end{aligned}$ .

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2 years ago

What is the vertex of the quadratic function f(x) = (x – 8)(x – 2)?

irakobra [83]

Answer:

Vertex (5 ,-9)

Step-by-step explanation:

Given : Function f(x) = (x – 8)(x – 2).

To find : What is the vertex of the quadratic function .

Solution : We have given that f(x) = (x – 8)(x – 2).

On removing parenthesis

f(x) = x²-2x -8x +16.

f(x) = x²-10x +16.

We need to find vertex of this function ,

Vertex: (h, k)

h = - $\frac{b}{2a}$ .

Plugging values

h = - $\frac{-10}{2(1)}$ .

h = 5 this is the x- coordinate,

Now , we will plug x= 5 in quadratic function .

k = (5)²-10(5)+16.

k = 25-50 + 16

k= -9.

Vertex (5 ,-9)

Therefore, Vertex (5 ,-9).

5 0

3 years ago

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