Given:
Atul has 
lb of candy.
Jose has 
lb of candy.
Maria has 
lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has lb less than Jose, therefore
Maria has = 
lb
Maria has = 
lb
Maria has = 
lb
Difference between the candies Atul and Maria have.
Difference = 
lb
Difference = 
lb
Difference = 
lb
Therefore, Atul have lb of candy more than Maria.
Answer:
0≤x≥3
2≤y≥4
Step-by-step explanation:
1) You will need to simplify both sides of the inequality.
2) Now you will need to subtract the like terms which leaves you with
We cannot do anything else so the answer will be
a<span>
ll real numbers are solutions.</span>
Answer:
60-11x < 20
Step-by-step explanation:
Let's first set out all the information we know.
- Jade has only $60, so we cannot go above the amount she has.
- She wants at LEAST $20 remaining
So, the first thing that will be in the inequality would be $60. Since you are wasting money, you have to subtract.
The thing that will be subtracted more than once is $11, so it will have the variable "x" added to it.
What we have so far is:
60-11x
Because this is an inequality, we will have a less than sign.
After that, we can conclude that $20 will come next because that is at the end of the problem.
So, the answer is:
60-11x < 20
Answer: $7.88
Step-by-step explanation: Twenty five percent of 31.50 is 7.875.
