If a2 -2ab + b2 = 9 and a![\begin{gathered} a^2-2ab+b^2=9 \\ aStep 1 factorize[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D9%20%5C%5C%20a%3C%2Fp%3E%3Cp%3E%EF%BB%BFStep%201%20%3C%2Fp%3E%3Cp%3Efactorize%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2%20%5C%5C%20%20%5Cend%7Bgathered%7D)
then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3
In the problem it is already given that Weston Laundry washed 285.38 pounds of towel and 353.47 pounds of sheets from local hotels in 1 day. Firstly we have to find the total pounds of linens that Weston Laundry has washed in 7 days. Then only will it be possible to find the amount of linen washed in a day.
Then t
Total linen washed by Weston Laundry in 7 days = (285.38 + 353.47) pounds
= 638.85 pounds.
Then
The amount of linen washed by Weston Laundry in 1 day = 638.85/7
= 91.26 pounds
So Weston Laundry washed about 91.26 pounds of linen each day.
Answer:
The answer is "The null hypothesis was rejected".
Step-by-step explanation:
Following are the right-tailed test:
Calculating the null and alternative hypothesis:

![= \frac{0.4267 - 0.3333}{[\sqrt{\frac{(0.3333 \times 0.6667)}{150}}]}\\\\= 2.426](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.4267%20-%200.3333%7D%7B%5B%5Csqrt%7B%5Cfrac%7B%280.3333%20%5Ctimes%200.6667%29%7D%7B150%7D%7D%5D%7D%5C%5C%5C%5C%3D%202.426)
Calculating the right-tailed test:

Therefore, we reject the null hypothesis.
This example shows that more than a third of the families own pets in this town.
5.333 OR 5 1/3
just plug it in the calculator
you will get your answer