Answer:
1-i and -1+i
Step-by-step explanation:
We are to find the square roots of 
. First, convert from Cartesian to polar form:
Next, use the formula ![\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5Bn%5D%7Br%7D%5Cbiggr%5B%5Ccis%5Cbiggr%28%5Cfrac%7B%5Ctheta%2B2%5Cpi%20k%7D%7Bn%7D%5Cbiggr%29%5Cbiggr%5D)
where 
to find the square roots:
<u>When k=1</u>
<u />![\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5B2%5D%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B2%7D%2B2%5Cpi%281%29%7D%7B2%7D%5Cbiggr%29%5Cbiggr%5D)
![\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B3%5Cpi%7D%7B4%7D%2B%5Cpi%5Cbiggr%29%5Cbiggr%5D)
<u>When k=0</u>
<u />![\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5B2%5D%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B2%7D%2B2%5Cpi%280%29%7D%7B2%7D%5Cbiggr%29%5Cbiggr%5D)
Thus, the square roots of -2i are 1-i and -1+i
Answer:
4 not equal to 0
Step-by-step explanation:
2(2)+2(0)+(0)=0
4+0+0=0
4=0
not equivalent
Answer:
91
Step-by-step explanation:
we will call Allen : A
we will call MIller: M
we will call James: J
The problem tells us we have three answers we need to find and it only gives us one of those answers. We can use that to find the other needed answers. We will start with answering the first one.
A = 44
We know from the given A = 44 so miller is half the weight we divide by 2.
A/2 = M
44/2 = 22 so we know that M is = to 22
then the question tells us james is three more than miller. we know from solving miller is 22.
M + 3 = J
22+3 = J
J=25
then the final question asks to add all of them together
A + M + J = Total weight
44 + 22 + 25 = Total Weight
91 = Total Weight
The function that represents the ordered pairs is C) y = 2x + 3 because the y-intercept is 3 and the only function that has this is y = 2x + 3.
