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Jobisdone [24]
3 years ago
6

The width of a rectangular rug is 7 feet and the length of its diagonal is 25 feet. What is the area?

Mathematics
1 answer:
Vika [28.1K]3 years ago
5 0
A=168 ft² 
 that's the answer hope it helped!<span>
</span>
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Factor each of the following expression completely..4a^2 b-8a^3 b^5+2ab^7.
Setler79 [48]
<span>Equation at the end of step  1  :</span><span> (((4•(a2))•b)-((8•(a3))•(b5)))+2ab7</span><span>Equation at the end of step  2  :</span><span><span> (((4•(a2))•b)-(23a3•b5))+2ab7 </span><span> Step  3  :</span></span><span>Equation at the end of step  3  :</span><span> ((22a2 • b) - 23a3b5) + 2ab7 </span><span>Step  4  :</span><span>Step  5  :</span>Pulling out like terms :

<span> 5.1 </span>    Pull out like factors :

  <span> -8a3b5 + 4a2b + 2ab7</span>  =  <span> -2ab • (4a2b4 - 2a - b6)</span> 

Trying to factor a multi variable polynomial :

<span> 5.2 </span>   Factoring   <span> 4a2b4 - 2a - b6</span> 

Try to factor this multi-variable trinomial using trial and error<span> 

 </span>Factorization fails

Final result :<span> -2ab • (4a2b4 - 2a - b6) </span>

<span>
Processing ends successfully </span>

<span>
</span>

<span>hope this helps hope i am brainliest i need it </span>

5 0
3 years ago
If a 42.9 foot tall flagpole casts a 253.1 foot long Shadow then how long is a shadow that 6.2 foot tall woman casts
soldi70 [24.7K]
The women's shadow would be 36.6ft. long. 
You have to set up a proportion   42.9             6.2
                                                       ---------   =   ------------ 
                                                        253.1               X
Then you cross multiply (6.2*253.1) and divide (1569.22/42.9) equals 36.6
5 0
3 years ago
PLEASE HELPPP URGENTTT!!!!
mario62 [17]
Go 14 miles east to pool
Go 9 miles north to school
Go 12 miles west to bank
5 0
3 years ago
Help please :)))))))))))))
natali 33 [55]

Answer:

D is the correct answer

if you want explanation you can comment down

6 0
3 years ago
Given () = −^3 + 2^2 +(3/2) be the position of a particle moving along the x-axis at time t. At what time will the instantaneous
cestrela7 [59]

Answer:

5.266 secs

Step-by-step explanation:

Lets assume ; p(t) = t^-3 + 2^2 + ( 3/2 ) is the particle position along x-axis

time interval [ 0, 4 ]

Average velocity = Displacement / time

                            = p( b ) - p( a ) /  b - a -------- ( 1 )

where a = 0 , b = 4 ( time intervals )

Back to equation 1

Average velocity = [ ( 4^-3 + 4 + (3/2) ) - ( 0 +  4 + (3/2) ) ] / 4

                             = 3.9 * 10^-3 ----- ( 2 )

Instantaneous velocity = d/dx p(t)

                                      = - 3/t^4  ------ ( 3 )

To determine the time that the instanteous velocity = average velocity

equate equations (2) and (3)

3.9*10^-3 = - 3 / t^4

t^4 = - 3 / ( 3.9 * 10^-3 ) = - 769.231

hence t = \sqrt[4]{- 769.231 } = 5.266 secs

we ignore the negative sign because time can not be in the negative

4 0
3 years ago
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