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3 years ago

The width of a rectangular rug is 7 feet and the length of its diagonal is 25 feet. What is the area?

Mathematics

1 answer:

Vika [28.1K]3 years ago

5 0

A=168 ft²
that's the answer hope it helped!<span>
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a bag containing some widgets weighing 81 kg. when 2 of the widgets are removed, the weight of the bag drops to 73kg. the bag wi

Sloan [31]

First I find the individual widget weight

81 - 73 = 2x
8 = 2x
x = 4

Then I find how many widgets were left

73 - 1 = 4y
72 = 4y
18 = y

Y is the amount of widgets left, therefore the amount left is 18

3 0

3 years ago

COLOR THEME Q ZOOM 1. The ratio of boys to girls at a dance was 9 to 5. How many girls were at the dance if there were 72 boys a

BabaBlast [244]

Answer:

72 boys=72:40

45 girls=81:45

90 girls=162:90

40 girls=72:40

etc.

Step-by-step explanation:

think of it as fractions

3 0

3 years ago

Teresa placed parentheses in the expression below so that its value was greater than 80. Write the expression to show where Tere

AlexFokin [52]

The x shows how they are meeting with the things to be with

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3 years ago

5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0

3 years ago

A computer code is based on the prime factorization of 160.Find the prime factorization of 160

lilavasa [31]

Ndhdjjdjdjshduhdjskakksjdnfbbfbbnfbbbdbdvdbdbbdbdbfhf

8 0

3 years ago