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3 years ago

If a 42.9 foot tall flagpole casts a 253.1 foot long Shadow then how long is a shadow that 6.2 foot tall woman casts

1 answer:

5 0

The women's shadow would be 36.6ft. long.
You have to set up a proportion 42.9 6.2
--------- = ------------
253.1 X
Then you cross multiply (6.2*253.1) and divide (1569.22/42.9) equals 36.6

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If f(x) and its inverse function, f^-1(x), are both plotted on the same coordinate plane, what is their point of intersection?

Romashka-Z-Leto [24]

Answer:

(a, a)

Step-by-step explanation:

actually there are two cases, don't have intersection and have. if have intersection, then they intersect at line y = x or point (a, a) by definition of inverse function.

8 0

3 years ago

Read 2 more answers

Aiko jump rope for an amazing 20 min she stopped at 8:05 when did she start

Scrat [10]

Aiko jump roped for 20 minutes before stopping at 8:05. Just count 20 minutes back in order to see when she started.

8:05 - 20 minutes = 7:45

6 0

3 years ago

Read 2 more answers

Find an equation for the line perpendicular to 2x+ 6y = 30 and goes through the point (6,2)

Mashutka [201]

Answer:

y = 3x - 16

Step-by-step explanation:

We are asked to find the equation of the line perpendicular to 2x + 6y = 30

We can use two formulas for this question, either

y = mx + c. Or

y - y_1 = m(x - x_1)

Step 1: calculate the slope

From the equation given

2x + 6y = 30

Make y the subject of the formula

6y = 30 - 2x

6y = -2x + 30

Divide both sides by 6, to get y

6y/6 = ( -2x + 30)/6

y = (-2x + 30)/6

Separate them in order to get the slope

y = -2x/6 + 30/6

y = -1x/3 + 5

y = -x/3 + 5

Slope = -1/3

Step 2:

Note: if two lines are perpendicular to the other, both are negative reciprocal of each other

Perpendicular slope = 3/1

Substitute the slope into the equation

y = mx + c

y = 3x + c

Step 3: substitute the point into the equation

( 6,2)

x = 6

y = 2

2 = 3(6) + c

2 = 18 + c

Make the c the subject

2 - 18 =c

c = 2 - 18

c = -16

Step 4: sub the value of c into the equation

y = 3x + c

y = 3x - 16

The equation of the line is

y = 3x - 16

If you try out the other formula, u will get the same answer

5 0

4 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

3 years ago

Write an expression to represent the product of 6 and the square of a number plus 15.

inn [45]

Answer:

6x² + 15

Step-by-step explanation:

Let the number be x.

"the square of a number"

x²

"the product of 6 and the square of a number"

6x²

"the product of 6 and the square of a number plus 15"

6x² + 15

The coefficient is the number that multiplies the variable, so it is 6.

8 0

3 years ago