Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
Answer:
A. Cellular respiration
C. Photosynthesis
Explanation:
There are two main processes occurs in the carbon cycle i.e. cellular respiration and photosynthesis. Plants absorb carbondioxide gas from the atmosphere through small openings called stomata. The carbondioxide enters the leaves and combine with water produces glucose and oxygen. Glucose is stored in different parts of plant whereas some oxygen is used by the plant and the remaining oxygen is releases in the atmosphere while on the other hand, in cellular respiration, glucose is broken down to produce energy in the form of ATP, carbondioxide gas and water.
Explanation:
By pizza,pasta, gelot and wine
Answer:
Leaves lose the most chloroplasts at the end of summer.
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