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tester [92]
3 years ago
13

Im literally sitting here crying my eyes out because i have so much homework due tomorrow someone please just help me with this

question i bet you its literally so easy im just really stupid someone please answer ill mark you brainiest, thank you, and rate 5 starts just please.
-
A point is a unit of length that can be used to measure the distance between two lines of text. Font sizes are often stated in points. Capitol letters measure two thirds of the stated point size, as shown in the diagram for a font size of 48 points. There are 72 points in 1 inch. What point size produces capitol letters that are 1/2 inches tall?

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
8 0

Answer:

I'm sorry you have a lot of Homework. All i know is the 1st step... i believe their are 3 steps to this question, I wish you the best of luck my friend!

Step-by-step explanation:

1st step =

x=36

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Students are to march in a parade. There will be one first grader, two second graders, three third graders, and so on, through t
Lana71 [14]
1+2+3+4+5+6+7+8+9+10+11+12=78
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4 0
4 years ago
Customers at your store select their groceries from shelves and then pay. Sales records and records of restocks for Flaming Roas
aleksandrvk [35]

Answer:

The net change is -2

Step-by-step explanation:

No. of bags     Tue  Wed   Thu   Fri   Sat   Sun   Mon

Sales                 5     8     2       19     22    15     3

Restock            6      12     12       18     24  0      0

Change in bags = Restock - Sales

Change in Tuesday = 6-5 = 1

Change in Wednesday = 12-8 = 4

Change in Thursday = 12-2 = 10

Change in Friday = 18-19 = -1

Change in Saturday = 24-22 = 2

Change in Sunday = 0-15 = -15

Change in Monday = 0-3 = -3

Net change = 1+4+10+(-1)+2+(-15)+(-3)=-2

Hence The net change is -2

7 0
3 years ago
Prove that sin^2A/cos^2A + cos^2A/sin^2A = 1/cos^2A*sin^2A - 2
jenyasd209 [6]

Answer:

prove that:

Sin²A/Cos²A + Cos²A/Sin²A = 1/Cos²A Sin²A - 2

LHS = \frac{Sin^2A}{Cos^2A} + \frac{Cos^2A}{Sin^2A}

Cos

2

A

Sin

2

A

+

Sin

2

A

Cos

2

A

= \begin{lgathered}= \frac{Sin^4A + Cos^4A}{Cos^2A . Sin^2A}\\\\Using\: a^2 + b^2 = (a+b)^2 - 2ab\\\\a = Cos^2A \: \& \:b = Sin^2A\\\\= \frac{(Sin^2A + Cos^2A)^2 - 2Sin^2A Cos^2A}{Cos^2A Sin^2A} \\\\Sin^2A + Cos^2A = 1\\\\= \frac{1 -2Sin^2A Cos^2A}{Cos^2A Sin^2A}\end{lgathered}

=

Cos

2

A.Sin

2

A

Sin

4

A+Cos

4

A

Usinga

2

+b

2

=(a+b)

2

−2ab

a=Cos

2

A&b=Sin

2

A

=

Cos

2

ASin

2

A

(Sin

2

A+Cos

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A)

2

−2Sin

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ACos

2

A

Sin

2

A+Cos

2

A=1

=

Cos

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ASin

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A

1−2Sin

2

ACos

2

A

\begin{lgathered}= \frac{1}{Cos^2A Sin^2A} - 2\\\\= RHS\end{lgathered}

=

Cos

2

ASin

2

A

1

−2

=RHS

LHS=RHS

4 0
3 years ago
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Answer:

0.61 or 61 %

Step-by-step explanation:

8 0
3 years ago
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