The answer would be variable.
hope this helped :)
<h3>c = 150 - 8s is the required function</h3>
<em><u>Solution:</u></em>
Given that,
Tyrone takes 8 pieces of candy from the bag each time he snacks
After eating 18 snacks, there are only 6 pieces of candy remaining in the bag
The number c of pieces of candy remaining in the bag is a function of s, the number of snacks Tyrone eats.
Therefore,
"c" is the number of pieces of candy remaining in the bag
"s" is the number of snacks Tyrone eats
Thus,
total number of candy in the bag = 
Remaining candy in the bag = Total candy - candy he ate
c = 150 - 8s
Thus the function is found
Answer:

Step-by-step explanation:
Given
Cost of Textbooks ---- Frequency
$25 up to $35 ----- 2
$35 up to $45 ------- 5
$45 up to $55 ------- 7
$55 up to $65 ------ 20
$65 up to $75 ---- -- 16
Required
Determine the relative class frequency for the $25 up to $35 class
First, we need to get the total frequency


Next, is to write out the frequency of $25 up to $35 class

Divide this frequency by the total frequency; This gives the relative frequency



Hence;
Option D answers the question
176 by multiplying 22 by 8
7 or 8 since 2 and a half hours isnt an even amount of time so thered be an extra 10 minutes