The perimeter:
The length of the longer side:
Answer:
? = 26 in
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
?² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )
? = 
= 26
That's "5 to the negative seventh power," and is equal to
1 1
---------- = --------- . I would accept "1/(5^7)" as correct.
5^7 78125
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
Answer:
(b) 
(a) 
Step-by-step explanation:
Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], whereas Parallel Lines have SIMILAR <em>RATE OF CHANGES</em> [SLOPES].
I am joyous to assist you anytime.
