Essentially this is asking you to sum the first three values of the geometric series that starts with i being 1 and has the rule of ( $8(\frac{1}{4})^{i-1}$ ).

Since we must sum the first <em>three </em>geometric values we need to see what the value of i will be for the first three. The sigma notation shows us that the first i will be equal to 1. This means the second i is 2 and the third i is 3.

Knowing this you can plug in the corresponding i values into ( $8(\frac{1}{4})^{i-1}$ ) and sum it all together

( $8(\frac{1}{4})^{1-1}$ ) + ( $8(\frac{1}{4})^{2-1}$ ) + ( $8(\frac{1}{4})^{3-1}$ )

( $8(\frac{1}{4})^{0}$ ) + ( $8(\frac{1}{4})^{1}$ ) + ( $8(\frac{1}{4})^{2}$ )

( $8(1)$ ) + ( $8(\frac{1}{4})$ ) + ( $8(\frac{1}{16})$ )

(8) + (2) + ( $\frac{1}{2})$ )

10 + $\frac{1}{2})$

$\frac{21}{2})$

10.5

Hope this helped!

~Just a girl in love with Shawn Mendes

8 0

3 years ago

Help on #3 above??? I will give brainliest!

Leona [35]

Answer:

$f(x)\rightarrow 1\ \text{as}\ x\rightarrow\pm\infty$

Step-by-step explanation:

"End behavior" generally refers to the behavior as the independent variable (x) gets large in the positive or negative directions. Here, the curve for large magnitude x flattens out and approaches 1. So, we say ...

$f(x)\rightarrow 1\ \text{as}\ x\rightarrow\pm\infty$

7 0

3 years ago

A fast-food company is interested in knowing the probability of whether a customer viewed an advertisement for their new special

lord [1]

Answer:

45% probability that a randomly selected customer saw the advertisement on the internet or on television

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a customer saw the advertisement on the internet.

B is the probability that a customer saw the advertisement on television.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a customer saw the advertisement on the internet but not on television and $A \cap B$ is the probability that the customers saw the advertisement in both the internet and on television.