Question

Of 50 people, 38 have brown hair, 29 have brown eyes, and 23 have both brown hair and brown eyes. how many have neither brown hair nor brown eyes?
A) 6 C) 10
B) 8 D) 12

Answer 1

Is it like this : 38+29=67 67-23=44
50-44=6
so perhaps A

Answer 2

Answer:

The correct option is A.

Step-by-step explanation:

Let A and B represents the following events.

A = Person have brown hair

B = Person have brown eyes

Given information:

Total people, S = 50

Person have brown hair, n(A)=38

Person have brown eyes, n(B)=29

Person have both brown hair and brown eyes, n(A∩B)=23.

The total number of persons have either brown hair or brown eyes is

$n(A\cup B)=n(A)+n(B)+n(A\cap B)$

$n(A\cup B)=38+29-23$

$n(A\cup B)=44$

The number of persons have neither brown hair nor brown eyes is

$S-n(A\cup B)=50-44=6$

Total 6 persons have neither brown hair nor brown eyes.

Therefore the correct option is A.