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SVEN [57.7K]
3 years ago
6

I need help with 1-2.b

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

it is a i thick

Step-by-step explanation:

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For a circle with a diameter of 6 meters, what is the measurement of a central angle (in degrees) subtended by an arc with a len
Sholpan [36]

Answer:

\boxed{\boxed{\theta=150^{\circ}}}

Step-by-step explanation:

We know that,

\text{Arc length}=r\cdot \theta

where,

r = radius,

θ = central angle in radian.

Given,

diameter = 6 m, so radius = 3 m.

\text{Arc length}=\dfrac{5}{2}\pi

Putting the values,

\Rightarrow \dfrac{5}{2}\pi=3\theta

\Rightarrow \theta=\dfrac{5}{2\times 3}\pi

\Rightarrow \theta=\dfrac{5}{6}\pi=\dfrac{5}{6}\times 180^{\circ}=150^{\circ}


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3 years ago
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You get 50 points if yu answer the question and the firdt to get it right gets top!!
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The equation would be:
3/4x=16 1/2
So you would divide both sides by 3/4
and get 44 bags for the leftover 16 1/2 lb. of cookies.
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A church has 8 bells in its bell tower. Before each church service 5 bells are rung in sequence. No bell is rung more than once.
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8!/5! = 40,320/120 = 336
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3 years ago
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Which of the following illustrates the truth value of the given conditional statement? If dogs have five legs, then cats have th
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Answer: In this conditional statement, all of the results are F.

There is no relationship between dogs having five legs and cats having three tails. Even if you took the converse and said "If cats have three tails, then dogs have five legs", there is no truth in that statement.
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3 years ago
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Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco
Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

d=136

The first part of the trip there was lots of traffic, she only averaged 16 mph;

v_1=16

The second part of the trip there was no traffic so she could drive 44 mph;

v_2=44

She traveled for a total of 5 hours;

t=5

let x represent the time in traffic when she traveled at 16 mph

t_1=x

the time the traffic is clear would be;

t_2=t-t_1=5-x

Recall that distance equals speed multiply by time;

d=v_1t_1_{}_{}^{}+v_2t_2

substituting the values;

136=16x+44(5-x)

solving for x;

\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}

So;

\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

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1 year ago
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