Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)
we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>
step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3
the midpoint AB is (3√2,2√3)
the answer isthe abscissa of the midpoint of the line segment is 3√2
see the attached figure
You have to distribute!
6(x) = 6x and 6(-6)=-36
So now you have 6x-36=-3(-x+3)
Now do the same on the other side.
-3(-x)=3x -3(3)=-9
So now, 6x-36=3x-9
Combine the like terms:
Subtract 3x in both sides.
6x-3x=3x
Now: 3x-36=-9
Add 36 in both sides.
3x=27
Divide by 3 on both sides to get x alone.
3x/3= x 27/3=9
X=9
The answer is D. I hope this helps love! :)
Insert the point, x=-30, y=3:
y=kx
3=k*-30
3=-30k
-1/10=k