All categories

4 years ago

Write a problem that can represent: 13x + 26 = 91

Mathematics

1 answer:

RUDIKE [14]4 years ago

3 0

13x+26=91
13x+26-26=91-26
13x=65 (Divide)
x=5
Hope this helps!

You might be interested in

What is the average?<br> 3458

Rina8888 [55]

Im guessing you meant whats the average of 3,4,5, and 8. which would be 5.

Add 3,4,5, and 8 and then divide by how many number you added up which would be 4.

4 0

3 years ago

Helppppppppppp me pls

Korolek [52]

Answer:

64 cubic feet.

Step-by-step explanation:

Volume is length times height times width.

It is all 4 feet, so it is 4 feet * 4 feet * 4 feet, or 64 cubic feet.

7 0

3 years ago

Read 2 more answers

Nitella [24]

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

<h3>How to find the production level that'll maximize profit?</h3>

The cost function, C(x) is given by 12000 + 400x − 2.6x² + 0.004x³ while the demand function, P(x) is given by 1600 − 8x.

Next, we would differentiate the cost function, C(x) to derive the marginal cost:

C(x) = 12000 + 400x − 2.6x² + 0.004x³

C'(x) = 400 − 5.2x + 0.012x².

Also, revenue, R(x) = x × P(x)

Revenue, R(x) = x(1600 − 8x)

Revenue, R(x) = 1600x − 8x²

Next, we would differentiate the revenue function to derive the marginal revenue:

R'(x) = 1600 - 8x

At maximum profit, the marginal revenue is equal to the marginal cost:

1600 - 8x = 400 − 5.2x + 0.012x

1600 - 8x - 400 + 5.2x - 0.012x² = 0

1200 - 2.8x - 0.012x² = 0

0.012x² + 2.8x - 1200 = 0

Solving by using the quadratic equation, we have:

x = 220.40 or x = -453.73.

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

6 0

3 years ago

What is the answer to 500 ÷60

Mama L [17]

8 1/3. 60×8=480. 500-480=20. 20 is 1/3 of 60.

6 0

4 years ago

15 POINTS PLEASE HELP!!! WILL MARK BRAINLIEST

dangina [55]

Given: ∠ DEF

To construct: ∠TSZ ≅ ∠DEF

Construction: Consider the attachment

Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST

Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.

Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.

Step-04: Now, join the point SQ and extend up to Z such that EF = SZ

Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF

6 0

3 years ago