So each time, 24/12 or $2 was deducted per trip
he has 30-24=$6 left
$6/$2=3, he has 3 trips left
I wonder what your question is
100+(34-(4+2)*3)/4
=100+(34-6*3)/4
=100+(34-18)/4
=100+16/4
=116/4
=29
29 is the answer
The relevant rules of exponents are
.. (t^a)^b = t^(a·b)
.. t^a·t^b = t^(a+b)
You have
.. (t^-4)^-9·t^2
.. = t^((-4)*(-9) +2)
.. = t^38 . . . . . . . . . . . selection C
57>X
hope this is what ur looking for
Answer:
A(0,-3) B (5,0) C(0,-7)D(5,-4)
Step-by-step explanation:
