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Oksanka [162]
3 years ago
7

at chengs bike rentals it costs 10 dollars to rent a bike for 3 hours. How many dollars does it cost per hour of bike use?

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0
The answer is 30 because 10 times 3 equals 30
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4 years ago
The complement of an angle is $5^{\circ}$ more than four times the angle. what is the number of degrees in the measure of the an
Anna11 [10]

Answer:

  17°

Step-by-step explanation:

Let x represent the measure of the angle.

  (90 -x) = 5 + 4x . . . . the complement is 5° more than 4 times the angle

  85 = 5x . . . . . . . . . . add x-5 to both sides

  17 = x . . . . . . . . . . . . divide by 5

The measure of the angle is 17°.

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4 years ago
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Reynaldo drew square EFGH. Then, he drew the image of it, square E'F'G'H', 4 centimeters to the left of the original figure. Lin
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6 centimeters

Step-by-step explanation:

Square E'F'G'H' is just square EFGH translated to the left.

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Line segment EF is the same length as segment E'F'.

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3 0
3 years ago
What is 9/36 equivalent to?
Ronch [10]
\frac{9}{36}=\\\\\frac{9:3}{36:3}=\boxed{\frac{3}{12}}\\\\\frac{9:9}{36:9}=\boxed{\frac{1}{4}}\\\\therefore\ \frac{9}{36}=\frac{1}{4}\\\\so,\ next\ equivalent\ fractions\ are:\\\\\frac{1\cdot2}{4\cdot2}=\boxed{\frac{2}{8}}\\\\\frac{1\cdot4}{4\cdot4}=\boxed{\frac{4}{16}}\\\\\frac{1\cdot5}{4\cdot5}=\boxed{\frac{5}{20}}\\\vdots\\and\ an\ infinite\ number\ of\ other
4 0
3 years ago
The y coordinate of the vertex of f (x)=-x^2+8x+7 is f(4)
azamat

Hello there.

To answer this question, we need to remember some properties about the vertex of quadratic functions.

Let f(x)=ax^2+bx+c,~a\neq0. Its vertex can be found on the coordinates (x_v,~y_v) such that x_v=-\dfrac{b}{2a} and y_v=-\dfrac{b^2}{4a}+c, in which y_v=f(x_v).

Using the coefficients given by the question, we get that:

x_v=-\dfrac{8}{2\cdot(-1)}\\\\\\ x_v=-\dfrac{8}{-2}\\\\\\ x_v=4

Thus, we have:

y=f(x_v)=f(4)

So the statement is true, because the x coordinate of the vertex of the function is equal to 4.~~\checkmark

7 0
2 years ago
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