Well basically by reading this question, I believe that if 75% sprout of the 20 seeds your equation would look like this 20(0.75) 0.75 is basically a simplified version of the 75% just written as a decimal so basically your answer would be 15 seeds ( so I believe you will be able to predict that 15 seeds will sprout! Let me know if this was either, helpful or non- helpful! I hope you have done a wonderful job!
Answer:
63.71 percent
Step-by-step explanation:
Answer:
a) Bar chart
b) Histogram
c) Bar chart
d) Histogram
Step-by-step explanation:
a) Trash pick-up DAY for each HOUSEHOLD in Ames - This is categorical data because, we are talking about days of the week. For instance, Household 1 might have Sunday as Trash pick-up day and that could be accumulated into frequency. Hence, BAR chart is the most appropriate.
b) Patient WAIT-TIME at ISU. This is continuous (quantitative) data. And the most appropriate is HISTOGRAM.
c) Number of trips taken during a GIVEN SCHOOL YEAR by EACH ISU STUDENT. Let say we have 5 ISU STUDENTS. Student 1 had 5 trips, student 2 had 10 trips, etc.
We want to see which student has the most and least trip in that particular school year. Although is count data but the most appropriate graphical display is BAR chart.
d) TAX BRACKET of ALL Iowa RESIDENTS. This is a continuous (quantitative) data. The most appropriate graphical display is HISTOGRAM.
Answer:
3π square units.
Step-by-step explanation:
We can use the disk method.
Since we are revolving around AB, we have a vertical axis of revolution.
So, our representative rectangle will be horizontal.
R₁ is bounded by y = 9x.
So, x = y/9.
Our radius since our axis is AB will be 1 - x or 1 - y/9.
And we are integrating from y = 0 to y = 9.
By the disk method (for a vertical axis of revolution):
![\displaystyle V=\pi \int_a^b [R(y)]^2\, dy](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V%3D%5Cpi%20%5Cint_a%5Eb%20%5BR%28y%29%5D%5E2%5C%2C%20dy)
So:

Simplify:

Integrate:
![\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V%3D%5Cpi%5CBig%5By-%5Cfrac%7B1%7D%7B9%7Dy%5E2%2B%5Cfrac%7B1%7D%7B243%7Dy%5E3%5CBig%7C_0%5E9%5CBig%5D)
Evaluate (I ignored the 0):
![\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V%3D%5Cpi%5B9-%5Cfrac%7B1%7D%7B9%7D%289%29%5E2%2B%5Cfrac%7B1%7D%7B243%7D%289%5E3%29%5D%3D3%5Cpi)
The volume of the solid is 3π square units.
Note:
You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

We acquire the exact same answer.
Answer:

Step-by-step explanation:
Given


See attachment for prism
Required
Find x
The prism has a regular hexagon base
The base area is calculated as:

This gives:




Side x represents the height.
So, we have:

Make x the subject




--- approximated