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2 years ago

Cadie is going to toss three coins simultaneously. What is the probability that exactly two of the coins will land on heads?

1 answer:

4 0

For each coin, there are <u>2 outcomes</u>, heads (H) or tails (T), so for the <u>3 coins</u>, the number of outcomes are:

2 x 2 x 2 = <u>8 outcomes:</u>

HHH / HHT / HTH / THH / TTT / TTH / THT / HTT

Out of all these outcomes, there are <u>3 ways</u>, we get exactly 2 Heads:

HHT / HTH / THH

So, the probability of exactly 2 coins landing on Heads is 3/8, or 0.375

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2 years ago

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Answer:

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2 years ago

Which of the following pairs of numbers contains like fractions? A. 5⁄6 and 10⁄12 B. 3⁄2 and 2⁄3 C. 3 1⁄2 and 4 4⁄4 D. 6⁄7 and 1

ElenaW [278]

<h2>Hello!</h2>

The answers are:

$\frac{5}{6}$ and $\frac{10}{12}$

$\frac{6}{7}$ and $1\frac{5}{7}$

To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.

We are given two fractions that are like fractions. Those fractions are:

Option A.

$\frac{5}{6}$ and $\frac{10}{12}$

We have that:

$\frac{10}{12}=\frac{5}{6}$

So, we have that the pairs of numbers

$\frac{5}{6}$

and

$\frac{5}{6}$

Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.

Option D.

$\frac{6}{7}$ and $1\frac{5}{7}$

We have that:

$1\frac{5}{7}=1+\frac{5}{7}=\frac{7+5}{7}=\frac{12}{7}$

So, we have that the pair of numbers

$\frac{6}{7}$

and

$\frac{12}{7}$

Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.

Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.

The other options are:

$\frac{3}{2},\frac{2}{3}$

and

$3\frac{1}{2},4\frac{4}{4}$

We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.

Hence, the answers are:

$\frac{5}{6}$ and $\frac{10}{12}$

$\frac{6}{7}$ and $1\frac{5}{7}$

Have a nice day!

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3 years ago

A football team received 3 penalties for 15 yards each, 1 for5 yards, and1 for half the distance to the goal from the 34- yard l

Effectus [21]

The first penalty they received is three 15 yards so total yards is 3(15 yards)
the second penalty is one 5 yard
the last penalty is half the 34 yard line(34 yard)/2
total change = 3(15 yards) + 5 yrad + (34 yard)/2
= 45 yards + 5 yards + 17 yards= 67yards

7 0

3 years ago