Question

Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth

Answer 1

Answer:

$\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$. Let $(x_1,y_1)\rightarrow(5,1)$ and $(x_2,y_2)\rightarrow(3,4)$, thus:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}$

Therefore, the distance between points P(5,1) and Q(3,4) is $\sqrt{13}$ units.