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olga2289 [7]
3 years ago
5

I need help please???!!!!

Mathematics
1 answer:
k0ka [10]3 years ago
8 0

Answer: 112

Step-by-step explanation:

7 + 7 = 14

14 + 14 = 28

28 + 28 = 56

56 + 56 = 112

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Ermias and Jeremiah both leave the bookstore at the same time, but in opposite directions. If Jeremiah travels 8 mph faster than
leva [86]

Using proportions, it is found that Ermias is traveling at a rate of 11 mph and Jeremiah at a rate of 19 mph.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Jeremiah travels 8 mph faster than Ermias, hence their velocities are:

x, x + 8

They travel in opposite directions, hence in one hour they are 2x + 8 apart.

In eight hours, the distance is 8(2x + 8), which is of 240 miles, hence:

8(2x +8) = 240

2x + 8 = 30

2x = 22

x = 11.

Then:

  • x = 11 -> Ermias.
  • x = 11 + 8 = 19 -> Jeremiah.

More can be learned about proportions at brainly.com/question/24372153

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3 0
1 year ago
A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s
mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, \theta=25°

Initial speed is, u=15\ m/s

Time of flight is, t=3.0\ s

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = -h (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, g=-9.8\ m/s^2

Now, using the following equation of motion;

-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, v_y=0\ m/s

Now, using the following equation of motion, we have:

v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m

Therefore, the maximum height of the brick is 2.05 m.

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3 years ago
What set of transformations is performed on LMNO to form L'M'N'O
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In order to answer this question I need to see a diagram. Do you have one?

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What is negative one / 3 plus the √10
marysya [2.9K]

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