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3 years ago

Chemistry : the atomic number of an element is 73. Is this paramagnetic or diamagnetic? :) ...?

2 answers:

5 0

Paramagnetic, an easy way to check is to see if it is the last element within the orbital and you can do that simply by looking at the periodic table. The s orbital has two, the p has 6 so on and so forth. Some elements are considered diamagnetic if they are almost completely full.

kupik [55]3 years ago

4 0

Answer:

paramagnetic

Explanation:

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

Given the atomic number - 73

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{10}4s^24p^64d^{10}5s^25p^64f^{14}5d^36s^2$

The electrons in 5d orbital = 3

These 3 will be unpaired as electrons are first singly filled.

Thus, the element is paramagnetic as the electrons are unpaired.

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3 years ago

Complete and balance the reaction in acidic solution. equation: ZnS + NO_{3}^{-} -> Zn^{2+} + S + NO ZnS+NO−3⟶Zn2++S+NO Which

kotykmax [81]

Answer:

Balanced reaction: $3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

S is oxidized and N is reduced.

$NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

Explanation:

Reaction: $ZnS+NO_{3}^{-}\rightarrow Zn^{2+}+S+NO$

$\Rightarrow$ Oxidation: $ZnS\rightarrow Zn^{2+}+S$

Balance charge: $ZnS-2e^{-}\rightarrow Zn^{2+}+S$ ...............(1)

$\Rightarrow$ Reduction: $NO_{3}^{-}\rightarrow NO$

Balance H and O in acidic medium : $NO_{3}^{-}+4H^{+}\rightarrow NO+2H_{2}O$

Balance charge: $NO_{3}^{-}+4H^{+}+3e^{-}\rightarrow NO+2H_{2}O$ ...............(2)

[ $3\times$ Equation-(1)] + [ $2\times$ Equation-(2)]:

$3ZnS+2NO_{3}^{-}+8H^{+}\rightarrow 3Zn^{2+}+3S+2NO+4H_{2}O$

Oxidation number of S increases from (-2) to (0) for the conversion of ZnS to S. Therefore S is oxidized.

Oxidation number of N decreases from (+5) to (+2) for the conversion of $NO_{3}^{-}$ to NO. Therefore N is reduced.

$NO_{3}^{-}$ consumes electron from ZnS. Therefore $NO_{3}^{-}$ is the oxidizing agent and ZnS is the reducing agent.

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4 years ago

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Viktor [21]

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Explanation:

The stability of a radioactive element can influence the rate of nuclear decay reaction. Pressure, temperature and concentration only affects chemical changes. These factors would not have any effect on radioactive decay of an element.

Every atomic nucleus have a specific neutron/proton ratio which ensures the stability of the nucleus.
Any nucleus that deviates from the stability ratio will continue to split until it achieves stability.
The more unstable a nucleus is, the faster it decays.
This is the basis of radioactive decay of elements.

Learn more:

radioactivity brainly.com/question/10125168

radioactive brainly.com/question/4207569

#learnwithBrainly

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hram777 [196]

Answer:

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