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2 years ago

(15 POINTS)

Mathematics

1 answer:

OleMash [197]2 years ago

7 0

Answer:

Step-by-step explanation:

$x^2-5x-6==\\\\x^2+x-6x-6=0\\\\x(x+1)-6(x+1)=0\\\\(x+1)(x-6)=0\iff x+1=0\ \vee\ x-6=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\\boxed{x=-1}\\\\x-6=0\qquad\text{add 6 to both sides}\\\boxed{x=6}$

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The solution system to 3y-2x=-9 and y=-2x+5

Alecsey [184]

Answer:

$\boxed{(3,-1)}$

Step-by-step explanation:

Hey there!

Well to find the solution the the given system,

3y - 2x = -9

y = -2x + 5

So to find x lets plug in -2x + 5 for y in 3y - 2x = -9.

3(-2x + 5) - 2x = -9

Distribute

-6x + 15 - 2x = -9

-8x + 15 = -9

-15 to both sides

-8x = -24

Divide -8 to both sides

x = 3

Now that we have x which is 3, we can plug in 3 for x in y = -2x + 5.

y = -2(3) + 5

y = -6 + 5

y = -1

So the solution is (3,-1).

Hope this helps :)

4 0

2 years ago

Geometry question plz help

saw5 [17]

Answer:

I think it would be 85 degrees.

6 0

2 years ago

A lab technician is dividing a cell that has a diameter of 4.32×10^-4 millimeters. Each of the new cells has a diameter measurin

RideAnS [48]

Answer:

$2.16 \times {10}^{ - 4}$

Step-by-step explanation:

The lab technician is dividing a cell that has a diameter of

$4 .32 \times {10}^{ - 4}$

The new cells has a diameter that is half of the diameter of the original cell.

The diameter of the new cell is given as:

$\frac{4.32 \times {10}^{ - 4} }{2}$

Rewrite the numerator in standard notation:

$\frac{0.000432}{2}$

$= 0.00216$

We rewrite in scientific notation to obtain:

$2.16 \times {10}^{ - 4}$

3 0

3 years ago

.Bryan was given the equation y= -5x+3. He says the rate of change is 3 and the initial value is -5. Is Bryan correct? If not, c

Mekhanik [1.2K]

Answer:

Correct rate of change is -5; correct initial value is 3.

Step-by-step explanation:

The rate of change is the coefficient of the x term, which here is -5. So Bryan has the rate of change wrong.

The initial value of the function is found by letting x = 0. Here, we get

y = -5(0) + 3, or y = b = 3. The initial value is 3, not -5.

8 0

2 years ago

What is the tan invers of 3i/-1-i

postnew [5]

z = 3i / (-1 - i )

z = 3i / (-1 - i ) × (-1 + i ) / (-1 + i )

z = (3i × (-1 + i )) / ((-1)² - i ²)

z = (-3i + 3i ²) / ((-1)² - i ²)

z = (-3 - 3i ) / (1 - (-1))

z = (-3 - 3i ) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(z) and Im(z) are negative. But arctan only returns angles between -π/2 and π/2. So we have

arg(z) = arctan((-3/2)/(-3/2)) - π

arg(z) = arctan(1) - π

arg(z) = π/4 - π

arg(z) = -3π/4

where I'm taking arg(z) to have a range of -π < arg(z) ≤ π.

6 0

2 years ago