(15 POINTS)

Mathematics

1 answer:

OleMash [197]3 years ago

7 0

Answer:

Step-by-step explanation:

$x^2-5x-6==\\\\x^2+x-6x-6=0\\\\x(x+1)-6(x+1)=0\\\\(x+1)(x-6)=0\iff x+1=0\ \vee\ x-6=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\\boxed{x=-1}\\\\x-6=0\qquad\text{add 6 to both sides}\\\boxed{x=6}$

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Step-by-step explanation:

Let P be any point on tangent $\overleftrightarrow{YZ}$ and WY is secant or chord of the $\odot J$ .

$\therefore m\angle WYZ + m\angle WYP = 180°\\(Straight \: line \: \angle 's) \\\therefore 104° + m\angle WYP = 180°\\\therefore m\angle WYP = 180°- 104° \\\red{\boxed {\bold {\therefore m\angle WYP = 76°}}} \\$

NOW, by tangent secant theorem:

$m\angle WYP =\frac{1}{2}\times m(\widehat{WXY}) \\\\76°=\frac{1}{2}\times m( \widehat{WXY}) \\\\76°\times 2 =m( \widehat{WXY}) \\\huge \purple {\boxed {\therefore m(\widehat{WXY}) = 152°}}$