(15 POINTS)

Mathematics

1 answer:

OleMash [197]2 years ago

7 0

Answer:

Step-by-step explanation:

$x^2-5x-6==\\\\x^2+x-6x-6=0\\\\x(x+1)-6(x+1)=0\\\\(x+1)(x-6)=0\iff x+1=0\ \vee\ x-6=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\\boxed{x=-1}\\\\x-6=0\qquad\text{add 6 to both sides}\\\boxed{x=6}$

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