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wolverine [178]
3 years ago
8

a large Bumble Bee beats its wings 2340 times and 13 seconds a honey bee beats its wings 1470 times in seven seconds which beats

its wings at a faster rate​
Mathematics
2 answers:
inn [45]3 years ago
8 0

Answer:

Honey bee

Step-by-step explanation:

Speed of bumble bee=2340/13

=180

Speed of honey bee=1470/7

=210

Since 210 is more than 180 hence the honey bee beats it's wings at a faster rate

guapka [62]3 years ago
7 0

Answer:

Bumble Bee: 180 beats per second

Honey Bee: 210 beats per second.

Step-by-step explanation:

To first figure this out, you need to convert this data into fractional ratios.

For this scenario (<em><u>beats/seconds</u></em>) so the fractions would be <em><u>\frac{2340}{13}</u></em> and<em><u> \frac{1470}{7}.</u></em>

Now that we have these we need to make the denominator equal 1. This will show us the beats per second for each bee. To do this divide the top and the bottom by the said denominator.

-

<em>Bumble Bee:</em>

<u><em>\frac{2340}{13} </em></u>

<u><em>\frac{2340/13}{13/13}</em></u>

<u><em>\frac{180}{1}</em></u>

<em>In this case, the Bumble Bee beats its wings at a ratio of </em><u><em>180 beats every second.</em></u>

<em>---------</em>

<em>Honey Bee:</em>

<u><em>\frac{1470}{7}</em></u>

<u><em>\frac{1470/7}{7/7}</em></u>

<u><em>\frac{210}{1}</em></u>

<em>In this case, the Honey Bee beats its wings at a ratio of  </em><u><em>210 beats per second.</em></u>

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1.    An AP has a common difference of 3.  Given that the nth term is 32, and the sum of the first n terms is 185, calculate the
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Answer:

The value of n is 10

Step-by-step explanation:

The formula of the nth term of the arithmetic progression is a_{n} = a + (n - 1)d

  • a is the first term
  • d is the common difference between each 2 consecutive terms
  • n is the position of the term

The formula of the sum of nth terms is S_{n} = \frac{n}{2} [2a + (n - 1)d]

∵ An AP has a common difference of 3

∴ d = 3

∵ The nth term is 32

∴ a_{n} = 32

→ Substitute them in the 1st rule above

∵ 32 = a + (n - 1)3

∴ 32 = a + 3(n) - 3(1)

∴ 32 = a + 3n - 3

→ Add 3 to both sides

∴ 35 = a + 3n

→ Switch the two sides

∴ a + 3n = 35

→ Subtract 3n from both sides

∴ a = 35 - 3n ⇒ (1)

∵ The sum of the first n terms is 185

∴ S_{n} = 185

→ Substitute the value of S_{n} and d in the 2nd rule above

∵ 185 = \frac{n}{2} [ 2a + (n - 1)3]

∴ 185 = \frac{n}{2} [2a + 3(n) - 3(1)]

∴ 185 = \frac{n}{2} [2a + 3n - 3]

→ Multiply both sides by 2

∴ 370 = n(2a + 3n - 3)

∴ 370 = 2an + 3n² - 3n

→ Substitute a by equation (1)

∴ 370 = 2n(35 - 3n) + 3n² - 3n

∴ 370 = 70n - 6n²+ 3n² - 3n

→ Add the like terms in the right side

∵ 370 = -3n² + 67n

→ Add 3n² to both sides

∴ 3n² + 370 = 67n

→ Subtract 67 from both sides

∴ 3n² - 67n + 370 = 0

→ Use your calculator to find n

∴ n = 10 and n = 37/3

∵ n must be a positive integer ⇒ 37/3 neglecting

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4 0
2 years ago
I need #14 done by tomorrow around 9-10:00. Thank you so much if you do. God bless you :3
Vinvika [58]

Answer:

A) $ \frac{1}{5} $

B) - 5

C) Not Possible

D) 5

E) $ \frac{-1}{5} $

  • Step-by-step explanation:
  • All integers are rational numbers. But not all rational numbers are integers.
  • All whole numbers are integers. But not all integers are whole numbers.

I am a rational number but not an integer. Located on the right of 0.

This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form $ \frac{p}{q} $.

From, the options $ \frac{1}{5} $ would fit this description.

I am a rational number and an integer but not a whole number.

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I am a whole number but not an integer.

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This means it is a positive integer. 5 would fit this description.

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